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Too many arguments?

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# 1  
Old 03-05-2009
Too many arguments?
I can't find anything wrong with this line of code, it works when there is one file in the directory but more than one i get a "too many arguements2 error

if [ -z $(ls $dname) ]; then


am i missing something?
# 2  
Old 03-05-2009
The command "$(ls $dname)" returns you the list of files in the directory ...
So, if you have more one file in it, your result is "if [ -z file1 file2 file3 ... ]" !!!

Try this :
Code:
if [ $(ls $dname | wc -l) -eq 0 ] ; then

Good luck
# 3  
Old 03-05-2009
Works a treat ...Thank you!
# 4  
Old 03-05-2009
Another way to do it without the pipe into wc:

Code:
if [ ! "$(ls -A $dirname)" ];then echo "empty dir";fi

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