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Insert Tabs / Indent text

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# 1  
Old 02-18-2009
Insert Tabs / Indent text
Hi,

i need replace the slash (/) with a newline (\n) and a tab (\t).

With 'find -type f' in a folder i got this output:
./1999/01/file1
./1999/01/file2
./1999/02/file1
./2000/04/file1
./2000/04/file2
./2000/04/file3
./2000/04/file4
./2000/06/file1
./2000/06/file2
./2000/06/file3
./2000/06/file4


This is the result what i want to get:
Code:
1999
     01
         file1
         file2
     02 
         file1
2000
     04 
         file1
         file2
         file3
         file4
     06
        file1
        file2
        file3
        file4

I try it with this one liner:
Code:
find -type f | tr '\/' '\n' | awk '!x[$0]++'

* find gives me the output
* tr removes the slashes with newline
* awk removes double entries

With this line a got a result like this:
.
1999
01
file1
file2
file3

This is close to that what i want, but i dont know how i indent the code now.

I found this Tree Homepage which looks nice, but dont meet my needs, because i must add various values to each entry.

Could somebody gives me a hint?

Thanks in advance.

Stefano
# 2  
Old 02-18-2009
a slightly different output format, but....
tree.awk:
Code:
#! /usr/bin/awk -f

# tree.10
# print nice tree from find(1) output and alike
# Example:
#       find dir | tree.awk

BEGIN{
        FS = "/";
        i = 0;
        while ( i++ <= ARGC )
        {
                if ( ARGV[i] ~ /(-h)|(-\?)/ )
                {
                        print "Usage: tree.awk [FS=field-separator] [file ...]"
                        EXIT=1;
                        exit 1;
                }
        }
}

function fineprint(branches)
{
        gsub(" ","    ", branches);
        gsub("[|]","& ", branches);
        gsub("`","&---", branches);
        gsub("[+]","&---", branches);
        return branches;
}

function mktree(number,branches,   tnumber)
{

        if (number > NR)
        {
                return number - 1;
        }

        tnumber = number;

        while (array["shift", number] < array["shift", tnumber + 1])
        {
                tnumber = mktree(tnumber + 1, branches" ");
                if (tnumber == NR) break;
        }

        if (array["shift", number] == array["shift", tnumber + 1])
        {
                array["slip", number] = branches"+";
        }

        if ((array["shift", number] > array["shift", tnumber + 1]) \
                || tnumber == NR)
        {
                array["slip", number] = branches"`";
        }


        return tnumber;
}

{
        array["shift", NR] = NF;
        array["name", NR] = $(NF);
}

END{
        if (EXIT)
                exit EXIT;

        for (i = 1; i <= NR; i++)
        {
                i = mktree(i, "");
        }

        for (i = 1; i <= NR; i++)
        {

                if (i > 1)
                {
                        lprev = length(array["slip", i - 1]);
                        lcurr = length(array["slip", i]);
                        if (lprev > lcurr - 1)
                                legacy = substr(array["slip", i - 1], 0, \
                                                lcurr - 1);
                        else
                                legacy = array["slip", i-1];
                        tail = substr(array["slip", i], length(legacy) + 1 , \
                                        lcurr - length(legacy));
                        gsub("[+]", "|", legacy);
                        gsub("`", " ", legacy);
                        array["slip", i] = (legacy)(tail);
                }

                printf "%s%s\n", fineprint(array["slip", i]), \
                                array["name", i];

        }
}

# 3  
Old 02-18-2009
Another approach:

Code:
find -type f |
awk -F"/" '
a[$2] && $3==a[$2] {print "\t\t" $4}
a[$2] && $3!=a[$2] {a[$2]=$3;print "\t" $3;print "\t\t" $4}
!a[$2]{a[$2]=$3;print $2;print "\t" $3;print "\t\t" $4} '

Use nawk or /usr/xpg4/bin/awk on Solaris.

Regards
# 4  
Old 02-18-2009
yeah, but I'd assume the OP would want a non-static 'depth'....
# 5  
Old 02-18-2009
MySQL [Solved] Insert Tabs / Indent text
Thanks to you. I decide me for the second version because its short and works for me.

@vgersh99: This folderstructure has a static depth of three levels
Code:
year
  month
    file

Could you explain what awk does, Franklin52?

Stefano
# 6  
Old 02-18-2009
Quote:
Originally Posted by Tonda
Could you explain what awk does, Franklin52?

Stefano
Sure, here we go:

Code:
find -type f |
awk -F"/" '
a[$2] && $3==a[$2] {print "\t\t" $4}
a[$2] && $3!=a[$2] {a[$2]=$3;print "\t" $3;print "\t\t" $4}
!a[$2]{a[$2]=$3;print $2;print "\t" $3;print "\t\t" $4} '

Code:
awk -F"/" '

Change the fieldseparator to a slash

Code:
a[$2] && $3==a[$2] {print "\t\t" $4}

If the element a[$2] of the array exists (not a new year) and the 3th field (number) is equal to the value of the element of the array (not a new number) print 2 tabs before the 4th field (filename)

Code:
a[$2] && $3!=a[$2] {a[$2]=$3;print "\t" $3;print "\t\t" $4}

If the element a[$2] of the array exists (not a new year) and the 3th field (number) is not equal to the value of the element of the array (we have a new number!), assign the value of the 3th field (number) to the element a[$2], print 1 one tab before the 3th field (number) and 2 tabs before the 4th field (filename) on separate lines

Code:
!a[$2]{a[$2]=$3;print $2;print "\t" $3;print "\t\t" $4} '

If the array a[$2] doesn't exist (we have a new year!) assign the value of the 3th field (number) to the element a[$2], print the 2nd field (year), one tab before the 3th field (number) and 2 tabs before the 4th field (filename) on separate lines


Regards
# 7  
Old 02-19-2009
What is in the arrays?
Ah, thanks Franklin52.

i read a introduction to awk and think i got the most of this code, but i have few question to the arrays.
From where come from, are they filled automaticly like $0 with the whole line? What is in there?

Stefano
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