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Hi,

Try this code. This will get the directory name as the parameter and rename all the filenames with "." in it. I hope the script will be easy for you to understand.


#!/bin/ksh
#Rename...

Try this


echo "the date is :\c"
date


--Mons

Hi,

Try this command



grep -v '^$' remove_wp.txt | sed -e 's/ //g' -e 's/ //g' | sed 'N;N;s/\n//g'




-Mons

Hi,

Try the following script


#!/bin/sh
errorexit ()
{
echo Error : $*
echo
}
stval=`cut -d, -f1 dir.conf`
errorcount=0
for dir in $stval
do
echo " this is $dir"
if [ ! -d "$dir" ]...

This might be complex but the below script will give you the dates lesser than the passed date


#!/bin/ksh
inputdate=`echo $1 | sed 's/^\(..\)\(..\)\(..\)$/\3\2\1/'`
for i in `sed...

I think you have posted your question in the wrong forum.

If you are using JSP try using request.getParameter method to capture

You dont have execute permission for the file Script.sh

Just run the following command to grant execute permission

chmod u+x Script.sh

-Mons

Why can't you echo the variable to sed and search and replace

echo "abcabc" | sed 's/a/x/g'

try the below sed command

echo "-i abcd-fe" | sed 's/-/X/2'

-S is to login to the sqlplus with SILENT option.

This suppresses all SQL*Plus information and prompt messages, including the command prompt, the echoing of commands, and the banner normally...

Which solution is not working? Give the last two digits for year

Try this command
You can include this in a shell script to get the month and year to pass to the below command.

cal 10 05 | grep -v ^$ | tail -1 | sed 's/^.* \([0-9]*\)$/\1/'