Search Results

I have solved the problem thanx any way...

Hi everybody

I already have installed Linux Red Hat FC4 in two machines into the same net using DHCP in both of them, the network interface are working fine cuz i can surf in Internet in those...

Hello everybody

I already read all the posts about "how to send email" but i dont find the solution, i need to send a mail via commands. Into the mail i need to attach a file.txt how can i do...

I use Digital Unix, and when i need something like you i do this:



$ cd /usr/local/bin
& top



And this show me all the CPU usage from the higest to the lowest, maybe you can send this to...

It works but it is still slow... there is not a way to do it with 'tail whatever'?

If you always want to get the last part after '_' do this



ls -1 | cut -d "_" -f2

Another thing, i dont understanw well the part of "but it displays the 3 first letters of all lines" that you post, please tell me exactly what kind of files do you have and what exactly you want as...

i dont speak english well but i think you need es to get the 3 first letters of a list of files right?

like in your first post, if the 4th letter is '_' do this:



ls -1 | cut -d "_" -f1 >...

the problem is that i cannot alter those file cuz is used to generate statistics

The script is:



wc -l file1 | grep EXACTO > my_file
sleep5
wc -l file1 | grep EXACTO >> my_file



so in my_file i get the number of lines, the difference between those are what i need...

At first time i try to get whe num of lines actual, then the num of lines in 5 seconds then the difference between they, but in 'file1' i have thousand of lines and a 'wc -l file1' take to much...

pixelbeat it still dont work, 'tail -f -s5 file1 works' but not just 5 seconds, it works like 'tail -f file1'

Hello everybody, how i can get how many lines are writed in a file in the last 5 seconds?

For ezample i have 'file1' that is filled by a process automatically and i neet to know how many lines...

Amit, your post help me, I just have to add some characters and at the end the solution was:

kill -9 `ps -aef | grep 'monitoreo start' | grep -v grep | awk '{print $2}'`


Thanx

use

| more

after your 'grep' commands

Hello guys,

I have a process named monitoreo, with 'monitoreo start' my process start until i kill them, now i want to do 'monitoreo stop' to kill them.

After 'monitoreo start' i have this...

Maybe i need to explain better what i have and what i need.

In 'errores.log' i have a lot of transactions logs, succesfull and with errors, another process fill this file in real time.

i want...

vgersh please could you explain me better your command? i maen, can i do:

tee -a <source> <new> ???

Hello again,

I have a script to read the last line writed in a file, make a grep and if the grep match, write this line into another file (that is what i want)

script
tail -f...

Part of my 'borrar' file:

[2005-06-10 07:28:11]{12}: [R-> PBRX1] DELIVER_SM_RESP [seqno: 79774][trans_id: 23914495 ][cmd_status: 0x00000064]
[2005-06-10 07:28:11]{13}: [R-> PBRX2] DELIVER_SM_RESP...

Radhika that's right u might use in crontab:

00,30 * *.......

Thanx criglerj your solutions works too, but now i have a new problem, the file borrar.log have 2537051 lines and this process is taking 30 seconds, and i need this information for bein showed each...

i got it....

nawk -f prueba.awk borrar

Thanx my friend vgersh99!!!!!!!!

Not yet, i still have problems:

example# nawk prueba.awk borrar

nawk: syntax error at source line 1
context is
>>> prueba. <<< awk
nawk: bailing out at source line 1

I don't know too much of awk, i just know that awk is powerfull as another, when i run the following script u have this problem:

awk: syntax error near line 1
awk: bailing out near line 1


...