Search Results

Thanks again for guiding me through this.

Here's my original grep:


gunzip -c L:\System1\SailLogger_20071019* L:\System2\SailLogger_20071019* L:\System3\SailLogger_20071019* | grep 35=Order...

Thanks. Not sure how to use this code:


$ cat x.dat75=20130130;60=074338;61=985;511=55473883;452=115439;62=196;267=1;$ sed -n 's/.*\(60=[0-9]*\).*\(511=[0-9]*\);.*$/\1 \2/p' x.dat60=074338...

Thanks again. When I run this:

U:\>gunzip -c L:\System1\SailLogger_20130130* | grep 35=SailOrderEntry

I get results like this:
...

Thanks again. Tried this:

U:\>gunzip -c L:\System1\SailLogger_20130130* | awk -F\; '{for(i=1;i<=NF;i++) { if($i ~ /^
60/) print $i; if($i ~ /^511/) print $i; }}'

And received this error:
...

Thank you. I tried this in a windows cmd:

U:\>gunzip -c awk -F\; '{for(i=1;i<=NF;i++) { if($i ~ /^60/) print $i; if($i ~ /^511/) print $i; }}'L:\System1\SailLogger_20130130*...

Thanks you. I tried this:

U:\>for %C in (L:\System1\SailLogger_20130130*.* L:\System2\SailLogger_20130130*.* L:\Syst
em3\SailLogger_20130130*.*) do ( gunzip %C | grep 35=SailErrorNotice )

It...

My grep returns a row of data like this:

75=20130130;60=074338;61=985;511=55473883;452=115439;62=196;267=1;

Is there a way for the grep to only return 60="something" and 511="something" ?
...

Thanks. Is it possible to do this in the windows CMD ?

This is for windows.

Hi. Yes. Each path has a differnt log (System1,2,3) that follows the same naming convention.

Hi Thanks for replying. Yes these logs are updating every 30 seconds. I tried this grep -

gunzip -c L:\System1\SailLogger_20130118* L:\System2\SailLogger_20130118* L:\System3\S...

Hello all. I am new to this forum and also very new to using grep - so please excuse me if this question is not in the correct forum and/or is not pertinent to this website.

I use greps like...