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# Function Declaration Start

echo -n "Enter Series Name : "
read series
echo -n "Bug Number : "
read bugNumber

n=`ade createview xyz -latest -series $series
n=`ade useview xyz` ----> here...

Hi All,

I am trying to create a shell script which runs on my linux machine.

The requirement is so that,
ade createview xyz -> this steps creates a view
ade useview xyz -> we are entering...

Thanks Pamu, it worked. :)
And thanks to zazzybob too, I will definitely look at those details once. I am sure then I will get to know where I was failing!! :b: :D

echo "******Select option:******"
echo "1 - script1"
echo "2 - script2"
echo "3 - script3"
read option
echo "You have selected" $option"."
if [ "$option" = "1" ]
then script1.sh...

Yes even then the errors remain same.
This one being at the top
line7 if[2=1]: command not found

It dint change the errors. what is the issue with then?

echo "******Select Option:******"
echo "1 - script1"
echo "2 - script2"
echo "3 - script3 "
read option
echo "You have selected" $option"."
if["$option"="1" ]
then...

How can we share a script without actually sharing the code?

I have 4 scripts in my system.

The end user has to execute the first file and based on the inputs (I am reading 1, 2 , 3 as options)...

And it worked!! :):)
Thanks a lot buddy :)

But how to make sure the tag <abc-ref> with value
abc.efg.hij.klm is the only one getting commented out? :confused::confused:
there are more than one <abc-ref> tags!

sed '/abc-ref/,/abc-ref/s/^/# /' file
This code puts # in front of every line.
Firstly I want to comment only this section out, something like
<!--abc-ref>
...

I have an xml file which has following code :

<abc-ref>
<abc-name>abc.efg.hij.klm</abc-name>
</abc-ref>


I want to comment this whole section out and I have written the following...