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Hi,
I am unable to get the full FS space, as /home is 100% utilized and after deleting unwanted files, its still 100%. After checking the du -sk * | sort -n output and converting it to MBs, the...

Hi All,

I've made a script in order to delete the users. The script is deleting the users and removing its entry from the /etc/sudoers however it is changing the permissions of the /etc/sudoers...

It was due to mail log size was 2 GB, its now resolved. Thanks for the help :)

Hi All,

I've tried starting syslogd on our hp-ux 11.31 server. However, it is not getting started nor it is updating the syslog file.

There is no space issue also. However, the mail.log file is...

The user which is executing the script is added into the sudoers of the remote machine also the permissions of the sudoers file are given below:


# grep -i testmgmt /etc/sudoers
testmgmt ...

Hi,

I am trying to edit the /etc/sudoers file using ksh, however I am unable to do that. Please find the code below:


ssh $i "/usr/local/bin/sudo /usr/bin/echo "$user_id ALL=(ALL) ALL" >>...

Hi,

I am unable to set the password remotely. I am using the script as below:



ep=`echo "$p" | /usr/lbin/makekey`

ssh -t $i "/usr/local/bin/sudo useradd -c "$user_c" -m -d /home/$user_id...

Thanks Don :)

That is really a useful information.

Thanks Krishmaths :)

Thanks Krishmaths,

However, I need flexible output not confined to one date. Like if the dates are 1 - 9 I can grep the first two values from date including the two spaces and after 9 i.e. from 10...

Can anyone help me in solving this ?

p=`date`
e=`echo $p | awk '{print $2,$3}'`
# echo $p
Wed Aug 4 12:00:08 IST 2013

but when I am echoing the value of e it is giving me with one space. As...