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in my list.txt contain
------------------
Mary 10
John 20

So, if i the name is not in the list like 'Marcus', it will return 0.
if the name exist in the list like 'John', it will return 20....

Why got two value display?

in my list.txt contain
------------------
Mary 10
John 20

So, if i the name is not in the list like 'Marcus', it will return 0.
if the name exist in the list like 'John', it will return 20....

Something like this
(if exist)? echo the value : echo 0

is it posible to make it ternary if else?

Yes, i need to write in the shell script.

---------- Post updated at 02:22 PM ---------- Previous update was at 02:21 PM ----------



The code you provided is unable to get the answer when i...

i want grep the value based on the name. If the name does not exist in the file return 0 ( mean grep nothing).

grep -c "Marcus" list.txt | awk '{print $2}'
it displays nothing.


What i want is
if i cant grep the keyword then
display zero
else
display the value

in a single line of code.

grep 'Marcus' list.txt | awk '{print $2}'


list.txt
Mary 10
John 20

How do i write if grep nothing then return zero instead of display nothing in the line.

This is what i got

grep: illegal option -- m
Usage: grep -hblcnsviw pattern file . . .

May i know where did i do wrong?

I want to valid a specific word whether it is contained in the text file. For example:

family.txt
father
mother
son
sister

if ("father" contain in family.txt)
do some process
else
...

Hi, ctsgnb
Thanks for your reply.
If i dont know the rows number in text, can it be captured based on the first value of a11111 ( like an unique value )?

Hi, ichaelrozar17
Thanks for the reply. It works perfectly.

Hi, cgkmal. Thanks for the reply.

I follow the code you provide
the system prompts this errors

awk: syntax error near line 1
awk: illegal statement near line 1
awk: syntax error near line 4...

How to edit file content at the specific line? For example at below

The things to edit --> This is line 2. And it is below line 1.


This is line 1.
This is line 2. # i want to...

I need crossover others platform between GNC and Suns. Suns can't run this code. Do you have other solution? Kindly appreciate your reply. TQ

val=21
total=3250
echo "`echo "scale=2; $val*100/$total" | bc`"

Output:
.64


How do i show the output become "0.64" instead of ".64" ?? Someone can help?

Can the date get from current date from system ?

can some one show me how to generate last hour of date for example:
2012010100 -> 2011123123 // check first date of a new year
2008030100 -> 2008022923 // check leap year as well
And also no...

Thank you. pravin27

how you show me how to store this result into a variable $target_date ?

I am using SunOS LSMS 5.10 .

date +%Y%m%d%H

output :
2011031415

I want to get previous hour like this 2011031414. Any one can help ?

I'm sorry i cant get it, i can't get it. If like the this how to run ? is it a function type?

{
echo "scale=2; $val1*100/$total" | bc
echo "scale=2; $val2*100*100/$total" | bc
...

May i know why got curly bracket?