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You can use this to get everything before the pattern yyy.
Here I used yyy pattern as field seperator.


cat file|awk -F 'yyy' '{print $1}'


Thanks

Gotam,

You can use the below code to test whether you got some rows using grep.....


count=`grep "search pattern" filename|wc -l`
if [ $count -ne 0 ]
then
echo "pattern match found"...

You can use the below code


for i in `cat file1`
do
for j in `cat file2`
do
echo "$j$i"
done
done


Thanks

Small correction to karthigayan's suggestion. instead of ./script.sh use . script.sh
Its working....

see the example below

user1@AIXCOE:/home/user1> pwd
/home/user1
user1@AIXCOE:/home/user1>...

Hi Arun,
You can use the following script ......


rm -r final 1>/dev/null 2>/dev/null
for i in `ls -l |grep -v total|sort +5|awk '{print $9}'`
do
cat $i >>final
done

Hi Samoo,

I have come up with a script for your requirement. When tested with sample files with same size it worked fine in deviding all files into 3 sets of equal size.

logic used :

Till...

Hi you can use the following Script ......

Script:
for file in `cat filelist`
do
rm -r ${file}-arr 1>/dev/null 2>/dev/null
count=1
while read line
do
if [ $(($count %...

Dear Amit,
You can also use the below script.....

cat data
abcd | fghfh | qwer | ertete
aaaa | bbbbb | cccc | dddddd

while read input
do
line1=`echo $input|awk -F\| '{print $1" |" $2" |"...