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Hi ,

Though Franklin's option works may be you can also try this

awk '{if($0~"}$"){print $0}}' <filename>

Hope this helps

Hi,

The command is

which
you can try
which ls
hope this helps

Hi Rahul,
Lets assume

$ a=gary,linux
$ echo $a
gary,linux ##output

Now

$ echo $a| awk 'BEGIN{FS=","}{print $1, " ", $2}'
gary linux ## output
...

oops I missed "Solaris" part completely :P

Hi ,

Try using

last -t 20080418220000 # format needs to be in sync with YYYYMMDDHHMMSS

Above command will list all the logins from the year 2008(20080418220000) starting from the day when...

here are the 2 file say "A" and "B"
file "A" contains
hey
the
output
is


while file "B" contains
hey
the
updated
output
later
is

Now if you try the command
diff A B

The output...

diff is the command for you

Ali , You can also use vi editor for your query

:%s/Search_string/Replace_str/g

try the following

sed -e's/SEARCH_STRING/REPLCE_STRING/g;' <filename>

Hi Krish,
You can try

sed -i -e's/SEARCH_STRING/REPLCE_STRING/g;' <filename>

if at all you wanna work with sed .I mean other than perl

Hi Ali ,
Though the above version is working fine for me you can try
sed -e's/SEARCH/REPLACE/g;' asd_dup.txt

Hi Diggi,
Hope this works for you .Let's assume we want to grab 3rd field for the current path
where
pwd=/home/gary/tobeExtracted

Now if we execute the following command
pwd |...

Deepak If you could please key in the output you want from your sample data :)

Hi Deepak ,

You can try "egrep "

egrep -a "foot|david" <filename>

This command will fetch you lines which contains foot or david.
Hope this helps:)

Thanks
Gaurav

Hi Arun,

If you are able to get the PID of the process you are concerned with then you get the "Files belonging to PID" using following command

lsof -p <PID>

Following command will give you the index of the pattern "WORD" in the string found

awk '{print match($0,/WORD/),RLENGTH }' <sample_File>

Please lemme know if you need some more details