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Hi,

I am using EXIT command to log out of the server, But this logs me out of the Putty. Is there any way that I can still be present on Putty and just log out of the server.

Every time I...

Hi ,



What is the significance of " $ " in [ ! -z $4 ] .



Kindly guide.

Regards

Hi,

I am a new user for LINUX. I have started learning C programming. I have heard that there is gcc & g++ compilers already available on LINUX by default.

Kindly guide where to find these...

if [ ! -e a.log ]; then
touch a.log
fi

...................................

if [ ! -f a.log ]; then
touch a.log
fi



Hi ,

Are the above two meant for same purpose i.e...

Hi ,

If "c.log" is a file. This file contains a number.

How to assign the content of file "c.log" as a variable ?

Please guide

regards

read iCOUNT < tmp_file.log

echo $fCOUNT > tmp_file.log

iCOUNT=$fCOUNT



I would really appreciate if you could explain the purposes of the above mentiond commands

Regards

1) There is only one file to be scaned

2)This file will be scaned after every 1 hour.

3) Let us suppose we scan the file right now . And suppose this gives us a count of ERROR as 5 . We will...

kindly advice ...how to proceed further ??

YES !! it worked.

Now this script will be run again after few minutes again.
At this time we need to take count in the fCOUNT in the last scan. This will be taken as the previous count of errors....

Actually I am trying to make a script that will scan for the errors in the log file. It will compare the previous count of the errors found in the last count with the current count of errors in the...

#!/bin/sh
findit=`find . -name "a.log" | wc -l`
if [ $findit -eq 0 ]; then
touch a.log
fi
iCOUNT=`grep ERROR a.log | wc -l`
while (1)
do
fCOUNT=`grep ERROR b.log | wc -l`
if [...

I think , it will move the last fCOUNT to a.log.

can I try as below ??



$fCOUNT > a.log

This should forward the count in fCOUNT to a.log. When the a.log was created there was no number into that. The number comes to fCOUNT. When the log file is scanned after few minutes , this fCOUNT...

#!/bin/sh
findit=`find . -name "a.log" | wc -l`
if [ $findit -eq 0 ]; then
touch a.log
fi
iCOUNT=`grep ERROR a.log | wc -l`
while (1)
do
fCOUNT=`grep ERROR b.log | wc -l`
if [...

Now I have extended the same script further for a comparison between counts of ERROR in two files .



#!/bin/sh
findit=`find . -name "a.log" | wc -l`
if [ $findit -eq 0 ]; then
touch a.log...

actually I am a bit confused between [ -eq 0 ] & [-eq 1 ]

can u please differetiate between these two ?

i think [ -eq 0 ] means condition is true or file found

&

[ -eq 1 ] means...

yes it is working !!!

but cant I make it like below ?



#!/bin/sh
findit=`find . -name "a.log" | wc -l`
if [ $findit -eq 1 ]; then
touch a.log
fi



I tried this but it did not work

Yes !!

It worked ...thanks

Now I am trying to make a script which creates a file "a.log" if it does not find the file "a.log"

I am using the following script.



#!/bin/sh
findit=`find...

I have tried the following script :-




#!/bin/sh
findit='find . -name "a.log" | wc -l'
if [ $findit -eq 0 ]; then
echo "1"
else
echo "0"
fi



and I am getting the below result when...

I have tried the following script :-




#!/bin/sh
findit='find . -name "a.log" | wc -l'
if [ $findit -eq 0 ]; then
echo "1"
else
echo "0"
fi



and I am getting the below result when...

Why are we using " wc -l " here ??

ok ...that means i have to declare the variable ....let me just try your way..

thanks...will inform you regarding the result...

Hi ,

I am trying the following simple script . But it is always giving 1 output. Dont know why



#!/bin/sh
find . -name "a.log"
if [ $? -eq 0 ] ; then
echo "1"
else
echo "0"
fi


...

./b.sh
/b.sh: line 7: syntax error near unexpected token `fi'
/b.sh: line 7: `fi'



now it is showing this error