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What you have tried so far ..

Your system is not supporting -i option in sed .. Try with the below then


for i in *.txt ; do printf ",s/^{{PreparerEmail.*}}$/{{PreparerEmail aaa@bbb.com}}\nw\nq\n" | ed $i ; done

Any errors ??

Expecting this ..

for i in hostlist.txt
do
ssh $i "hostname ; df -Ph ; hostname : \$\(df -Ph | wc -l\)" >> /tmp/vvv
done
echo "$(wc -l < /tmp/vvv)" ; cat /tmp/vvv

Extract the sql part alone.. try the below ..

while read line
do
error_msg[$index]="$(echo $line)"
index=`expr $index+1`
done <"logs/$ffile"
rows_count=${#error_msg
}
i=0
while [ $i -lt...

Performance not tested .. To avoid arithmetic calculations, try with egrep

$ egrep "83 (1...$|2000)" infile
83 1453
$

Try executing the script with debugging option by adding set -x on the lines top.

Why not while loop .. Expecting this ..??

while IFS=, read v1 v2 v3 v4
do
echo "USAGE $0 $v1 $v2 $v3 $v4"
done < infile

Expecting this .. ??

$ nawk '{$1=$1}; {sum+=$1}END{print sum}' infile
422.809

Include the exit scenario in test.pl perl script .. Post the code of it ..

$ sed "s,..:..-,$(date +%Y)-,g" infile
hostname 2007-Feb-9 /u100/DEVCO/Patching a.log
hostname 2010-Jun-25 /u100/DEVCO/DumpCleaner a.log
hostname 2011-Jun-25 /u100/DEVCO/DumpCleaner/sample a.log...

Oh My God .. I forgot :D

Directly executing the displayed output (without creating a temporary file and then execute it) ..

Try ..

ps -aux | grep mine | nawk '{split($15,b,"/"); print $1,$2,b[7]}'

What you have tried so far ..

---------- Post updated at 04:28 PM ---------- Previous update was at 02:51 PM ----------

@ roro , For your attention :...

Expected output format ??

One way .. (Include the highlighted part once satisfies with displayed output)

$ find dir_path -name "init*.ora" -type f | awk '{print "echo test123 >> "$0}' | sh

if [ -f "$file_name" ]; then
echo File $file_name Found
else
echo File $file_name Not Found
fi


Alternate one ..

$ [ -f "$file_name" ] && echo "Filename $file_name Found"...

Use nawk for Solaris machines ..

Similar post : https://www.unix.com/shell-programming-scripting/180835-sort-each-row-horizontally-awk-any.html

One more way .. (Based on the input given)

$ nawk '{$1=$1};1' infile | paste -d" " - - - - -
TT0000013101640| HCAMBLAMCNB010|Jul 3 2012 11:14AM| HARYANA| Bangali Mohalla |...

$ paste - - - < infile
USER_ID 12/31/69 19:00:00 12/31/69 19:00:00
USER_ID 12/31/69 19:00:00 12/31/69 19:00:00
USER_ID 12/31/69 19:00:00 12/31/69 19:00:00
USER_ID 12/31/69...

Try this for extracting secondary group id ..

$ secondary_group=$(id -a | tr ' ' '\n' | nawk -F"[(),=]" '/groups=/ {if($0~/\,/){print $5}else{print $2}}')

Only these 3 strings A756 or B234 or C987 to check ??? If NO, then on what basis, we can get the values of string from the input file ..

Be clear while providing the input and dont let us...

@amanda, your expected output shows, just a paragraph printing .. If yes, try the below ..

$ nawk '/ak3/,/ak12/' infile
1 ak3 abc1.0
1 ak4 abc1.0
1 ak5 abc1.1
1 ak6 abc1.1
1 ak7 abc1.1
1 ak8...