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guys rep pls!!!


i hv one more prob.. now this is another simple stuff tht i m stuck wid..

i wanna use grep in a if-else statement... but thrs a prob here

if [ !( grep -q pattern1 MyFile) ...

thnx..

but 1 more thing.. '\n' doesnt work gives the new line data in the same line..

sed "/pattern/ s/$/\nNew Row/" file

output
old data1
old data2
old data3
old data4
old data5
old...

i got this err..

> sed -i "/pattern/ s/$/\nNew Row/" filesed: illegal option -- i
Usage: sed [-n] Script [File ...]
sed [-n] [-e Script] ... [-f Script_file] ... [File ...]

help me...

i wanna insert a row in a file.

I m using this command to insert a row in the 13th line.
sed '13i\
NewRow' MyFile > temp.txt
mv temp.txt to MyFile

this works fine.
now i wanna get the line...

how can we add or subtract days from the output of date command in unix...

like if i want to subtract a day from the result of date command like this..
v_date=`date +%Y%m%d`
this wud give me...

thnx man!!!

how to grep the line no of the first pattern match in a file having multiple line of pattern match.

linke i want to know the line no for the word "the" the first time it appears in the file, now...

thnks man.. it helped

line_no=6
echo 'Phone,' `awk 'NR==$line_no{print;exit}' <filename>`

what is the error in this..

it says..
awk: Field $() is not correct.

The input line number is 1. The file is...