Red Hat

Hi Folks,

I want to run the below command and to exclude the specific path like /var/test/support/... . How to achieve using the below command

Code:

find / -type f \( –perm –4000 –o –perm –2000 \) –print

-Siva

Moderator's Comments:

Please do not use FONT tags inside CODE tags. And, there is usually no reason to use FONT tags at all when posting in this forum.

You haven't told us what operating system or version of find you're using. With a standards-conforming find utility, you could use:

Code:

find / -type f \( -perm -4000 -o -perm -2000 \) | grep -v '^/var/test/support/'

If the man page for the find utility on your system includes a -path primary, you could try the following. If you find supports this primary, this version should be faster:

Code:

find / \( -type d -path '/var/test/support' -prune \) -o \( -type f \( -perm -4000 -o -perm -2000 \) \)'

You could add -print to the end of either one of the above find commands and not change the results.

Hi Don,

I am using Redhat Linux and the command you have given has perfectly worked out for me..

Thanks..