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Get up one directory of location as variable

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Operating Systems Linux Red Hat Get up one directory of location as variable
# 1  
Old 03-28-2012
Get up one directory of location as variable
May i know how can i pass up one of a location to a variable in script file with command in stead of hardcode?

saying in my script file:

Code:
maindir = "/opt/xSystem/config"
upOneDir = ?????
echo $upOneDir

I have to use command to pass "/opt/xSystem"
to variable upOneDir.

Please advise..

many thanks!
# 2  
Old 03-28-2012
Code:
echo $mainder |awk -F/ '{gsub($NF,"");print}' |sed 's/.$//'

This User Gave Thanks to ningy For This Post:
cielle
# 3  
Old 03-28-2012
hello Ningy,

thanks for your prompt reply.

I have tested your advice but still unable to get the thing work.

Please advice again.
Thank you

---------- Post updated at 04:34 AM ---------- Previous update was at 03:39 AM ----------

and why below only works for pwd.. but not other location..

Code:
dir1=$PWD
echo $dir1

higher_dir=$(cd ..
pwd)
echo higher_dir

this doesn't work when i replace the $PWD with "/opt/xSystem"

please advice..

Many thanks!
# 4  
Old 03-28-2012
what output did u get when u ran my command above coz it worked for me..
# 5  
Old 03-28-2012
What shell do you use? In case of bash there are some nice string manipulation features:
Code:
maindir=/opt/xSystem/config
upOneDir=${maindir%/*}
echo $upOneDir
/opt/xSystem

This User Gave Thanks to cero For This Post:
cielle
# 6  
Old 03-29-2012
hello ningy..

it shows the blank.. hmm i did edit "maindir" from your code

thanks yea

---------- Post updated at 12:22 PM ---------- Previous update was at 12:21 PM ----------

hi cero,
thanks! it is working.
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