Just a simple question (which may seem silly so bear with me) that arose in my mind the other day. Do ASCII characters by themselves (e.g. /n, 0, a) have an actual memory address ?

My question arises, because Im aware that each time I create and initalise a pointer like this for example

int *ptr = 5;

Yes they do. Your declaration creates a pointer but does not constrain it to a variable of type int. Does your code compile okay and on what compiler?

For the code I spoke of in my first post,

int *ptr=5;

char *str="helloworld\n";
printf("string value is %s\n",*str)

int *ptr=5;

char *str="helloworld\n";
printf("string value is %s\n",*str)

printf("string value is %s\n", str);

printf("str points to %c\n", *str);

So this is always the case (except for user-defined strings) in real world programming, even though individual ASCII characters (such as 5) have memory addresses ?

Yes ASCII characters have memory addresses though 5 is an integer not an ASCII character. To be intrepreted a character in C it needs to be in single quotes.

char v = '5';

Shamrock, another question do individual integers, f. point numbers and doubles have mem. addressess as well ?

thanks for your help