Array Elements Check


 
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# 8  
Old 01-12-2015
Code:
akshay@Aix:/tmp$ cat tmp.c 
#include <stdio.h>
#define N_ELEMENTS(array) (sizeof(array)/sizeof((array)[0]))


void main() {
    int i, x, arr[10];

    printf("Enter a word: ");

    for (i = 0; i < 10; i++) {
        scanf("%d", &x);
        arr[i]=x;
    }
   
    for (i = 0; i < N_ELEMENTS(arr); i++) { printf("%d\n",arr[i]);
        if (arr[i] != arr[i + 1]) {
            printf("The array has different elements\n");
	    return ;
        }
    }

  
    printf("The array has similar elements\n");
}

Code:
akshay@Aix:/tmp$ gcc tmp.c

Code:
akshay@Aix:/tmp$ ./a.out 
Enter a word: 1 1 1 1 1 1 1 1 1 1
1
1
1
1
1
1
1
1
1
1
The array has similar elements

Code:
akshay@Aix:/tmp$ ./a.out 
Enter a word: 1 2 3 4 5 6 7 8 9 10
1
The array has different elements

This User Gave Thanks to Akshay Hegde For This Post:
# 9  
Old 01-12-2015
Quote:
Originally Posted by IgorGest
Yeah, of course. I can't understand why it doesn't work. SmilieSmilieSmilie
I'm using Eclipse with Windows. I'm going mad! Smilie
I hear ya. I had issues like that using Geany in Linux. Might be the compiler. It compiles and runs well from a terminal though.
Code:
gcc tmp.c -o tmp


Last edited by ongoto; 01-12-2015 at 02:16 PM..
# 10  
Old 01-12-2015
This is what's going wrong:

Code:
scanf("%d", &x);

The first time you run it, it sees a number and scans it.

The second time you run it, it hits whitespace of some sort -- a space or newline. This is not a digit, so it gives up.

The third time you run it, it hits the same whitespace. It's going to just keep slamming its head into the wall over and over again.

In summary, don't use scanf, it's a royal pain. Read lines yourself, tokenize them yourself, then use sscanf if you must. It will never pull this trick on you.

Code:
char buf[512];
int arr[10];

while(fgets(buf, 512, stdin))
{
        int n=0;
        char *tok=strtok(buf, " \r\n\t"); // Split on any whitespace, including newlines (which fgets includes).

        while(tok != NULL)
        {
                if(sscanf(tok, "%d", arr+n) != 0)
                {
                        n++;
                        tok=strtok(NULL, " \r\n\t"); // Keep splitting on the last string we gave it until done.
                        continue;
                }

                break;
        }

        printf("scanned %d numbers\n", n);
}


Last edited by Corona688; 01-12-2015 at 01:37 PM..
# 11  
Old 01-26-2015
Quote:
Originally Posted by Corona688
This is what's going wrong:

Code:
scanf("%d", &x);

The first time you run it, it sees a number and scans it.

The second time you run it, it hits whitespace of some sort -- a space or newline. This is not a digit, so it gives up.

The third time you run it, it hits the same whitespace. It's going to just keep slamming its head into the wall over and over again.

In summary, don't use scanf, it's a royal pain. Read lines yourself, tokenize them yourself, then use sscanf if you must. It will never pull this trick on you.

Code:
char buf[512];
int arr[10];

while(fgets(buf, 512, stdin))
{
        int n=0;
        char *tok=strtok(buf, " \r\n\t"); // Split on any whitespace, including newlines (which fgets includes).

        while(tok != NULL)
        {
                if(sscanf(tok, "%d", arr+n) != 0)
                {
                        n++;
                        tok=strtok(NULL, " \r\n\t"); // Keep splitting on the last string we gave it until done.
                        continue;
                }

                break;
        }

        printf("scanned %d numbers\n", n);
}

It works! Thank you for solving my problem. Smilie
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