Testing floating point numbers


 
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# 1  
Old 02-04-2011
Testing floating point numbers

Hi guys

I have problem with my simple calculator, author of my book wrote

Quote:
Store all values as floats. Whenever an is reguired , determine whether the fractional part of the number is zero
One way I tried is to test if one the inpur number is grater than zero, and then substatct

And my protptype function is
Code:
#include <stdio.h> 

int main(void) {
    
    float a, b , result;
    
    printf("\t\tThis program is only a test for %% C function\n");
    printf("Enrer two numbers: ");
    scanf("%f %f", &a, &b);
    
    // Test if input number has fractional part or not 
    
    if ( (a > 0) && (a - (int) a ) == 0 && (b > 0) && (b - (int) b ) == 0) {
        (int) (result = ((int) a) % ((int)b));
        printf("Result: %d\n", result);
        return 0;
      }
    else if ( (a < 0) && a + ( (int) - (a) ) == 0 && (b < 0) && b + ( (int)-(b) ) == 0) {
        (int) (result = ((int) a) % ((int)b));
        printf("Result: %d\n", result);
        return 0;
      }
    else if ( (a > 0) && (a - (int) a ) == 0 && (b < 0) && b - ( (int) - (b) ) == 0) {
        (int) (result = ((int) a) % ((int)b));
        printf("Result: %d\n", result);
        return 0;
      }
    else if ((a < 0) && a - ((int)-(a)) == 0  && (b > 0) && (b - (int) b ) == 0) {
        (int) (result = ((int) a) % ((int)b));
        printf("Result: %d\n", result);
        return 0;
        }
    else
        printf("Cannot perform action\n");
        return 1;
    }

But this is too complicated for basic calculator. I don't my C code look like spaghetti.

My simple algorithm (flowchart) is what I have on my mind, but litle black box (diamond) is that I don't know how to implement in

http://img62.imageshack.us/img62/4655/diagram1o.jpg

Last edited by solaris_user; 02-04-2011 at 05:40 AM..
# 2  
Old 02-04-2011
I guess the author wants you to use the floor() function:

Code:
int fraction_is_zero(double val)
{
     double b=floor(val);
     int retval=(b>0) ? 0 : 1;
     return retval;
}

floor() finds the largest whole number (integer) less than val. This function
returns 1 if the largest whole number == val. or the fractional part of the number is zero.
# 3  
Old 02-08-2011
Jim thanks for your answer but I don't think the author ment to use the floor() function because for now I only solved begginer C exercizes.

But I will try it to implement Smilie
# 4  
Old 02-08-2011
Are you at least allowed to use abs()?

Code:
int ival=(int)fval;
float d=abs(fval-ival);
if(d < 0.000000001)
{
        printf("Float %f has no fractional part\n");
}

== with floating almost never works because of the many digits of accuracy, but < > are reliable.

Last edited by Corona688; 02-08-2011 at 03:45 PM..
# 5  
Old 02-10-2011
Have you come across the bitwise operators yet...as this can easily be solved using them.
# 6  
Old 02-11-2011
Quote:
Originally Posted by shamrock
Have you come across the bitwise operators yet...as this can easily be solved using them.
bitwise operators -- on floating point numbers? You're assuming certain formats and endian-nesses of floats, and having to do pointer typecast tricks to get at the bits at all.
# 7  
Old 02-11-2011
Quote:
Originally Posted by Corona688
bitwise operators -- on floating point numbers? You're assuming certain formats and endian-nesses of floats, and having to do pointer typecast tricks to get at the bits at all.
Why would endianness matter if program is run on the same machine it is compiled on...and all follow the IEEE format on unix/linux flavors.
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