RE_COMP(3) Linux Programmer's Manual RE_COMP(3)NAME
re_comp, re_exec - BSD regex functions
SYNOPSIS
#define _REGEX_RE_COMP
#include <sys/types.h>
#include <regex.h>
char *re_comp(const char *regex);
int re_exec(const char *string);
DESCRIPTION
re_comp() is used to compile the null-terminated regular expression pointed to by regex. The compiled pattern occupies a static area, the
pattern buffer, which is overwritten by subsequent use of re_comp(). If regex is NULL, no operation is performed and the pattern buffer's
contents are not altered.
re_exec() is used to assess whether the null-terminated string pointed to by string matches the previously compiled regex.
RETURN VALUE
re_comp() returns NULL on successful compilation of regex otherwise it returns a pointer to an appropriate error message.
re_exec() returns 1 for a successful match, zero for failure.
ATTRIBUTES
For an explanation of the terms used in this section, see attributes(7).
+---------------------+---------------+-----------+
|Interface | Attribute | Value |
+---------------------+---------------+-----------+
|re_comp(), re_exec() | Thread safety | MT-Unsafe |
+---------------------+---------------+-----------+
CONFORMING TO
4.3BSD.
NOTES
These functions are obsolete; the functions documented in regcomp(3) should be used instead.
SEE ALSO regcomp(3), regex(7), GNU regex manual
COLOPHON
This page is part of release 4.15 of the Linux man-pages project. A description of the project, information about reporting bugs, and the
latest version of this page, can be found at https://www.kernel.org/doc/man-pages/.
GNU 2017-09-15 RE_COMP(3)
Check Out this Related Man Page
RE_COMP(3) Linux Programmer's Manual RE_COMP(3)NAME
re_comp, re_exec - BSD regex functions
SYNOPSIS
#define _REGEX_RE_COMP
#include <sys/types.h>
#include <regex.h>
char *re_comp(const char *regex);
int re_exec(const char *string);
DESCRIPTION
re_comp() is used to compile the null-terminated regular expression pointed to by regex. The compiled pattern occupies a static area, the
pattern buffer, which is overwritten by subsequent use of re_comp(). If regex is NULL, no operation is performed and the pattern buffer's
contents are not altered.
re_exec() is used to assess whether the null-terminated string pointed to by string matches the previously compiled regex.
RETURN VALUE
re_comp() returns NULL on successful compilation of regex otherwise it returns a pointer to an appropriate error message.
re_exec() returns 1 for a successful match, zero for failure.
ATTRIBUTES
For an explanation of the terms used in this section, see attributes(7).
+---------------------+---------------+-----------+
|Interface | Attribute | Value |
+---------------------+---------------+-----------+
|re_comp(), re_exec() | Thread safety | MT-Unsafe |
+---------------------+---------------+-----------+
CONFORMING TO
4.3BSD.
NOTES
These functions are obsolete; the functions documented in regcomp(3) should be used instead.
SEE ALSO regcomp(3), regex(7), GNU regex manual
COLOPHON
This page is part of release 4.15 of the Linux man-pages project. A description of the project, information about reporting bugs, and the
latest version of this page, can be found at https://www.kernel.org/doc/man-pages/.
GNU 2017-09-15 RE_COMP(3)
Hello
I need to make a regex.
I have a file myfile, in this file I want to find a number situated after PAYSLOT=
Before PAYSLOT is the begining of line (I guess ^) and
after the number is the end of line (I guess $) .
I want to echo this number (I guess $1) and put it in my variable payslot.... (5 Replies)
Hi guys,
Pretty new to regex, and i know im doing something wrong here. I'm trying to get a regex command that restricts a string to be 8 characters long, and the first character cannot be 0. Here's what i have so far...
echo "01234" | grep "^{8}*$"
Thanks very much!
-Crawf
... (7 Replies)
Morning folks,
I need help with the following issue:
Let's say we I have the following output:
First Name: Test
Last Name: Test2
Number: T1234
Number2: T1234
Needed Output:
T1234
Now I want to grep/nawk/printf/sed out the Number: (13 Replies)
I have got numbers like
l255677
l376039
l188144
l340482
l440700
l254113
to match the numbers starting with '13' what would be the regex
=~/13(.*)/ =======>This is not working ....
But for user123,user657
regex =~/user(.*)/ ========>works
Thanks for help..!! (7 Replies)
Hi all
I am struggling to find out the capturing regex of a date format such as 10/12/2009. Also I need help on how to assign the date(i.e, 10/12/2009 ) to a variable after the match is found using the capturing regex.
Any help is appreciated. Thanks in advance. (5 Replies)
Hi there,
How can we use regex in perl to store the Route Distinguisher (the bold field) and also the underlined and bold lines in the below file?
Note:
These highlighted pattern is redundant through the whole input file. Basically, we just need to extract these fields at least to store them... (4 Replies)
Need some help with a regex if loop problem.
File1:
2323
3232
4230
3230
4340
4343
233
32320
I want to print "Zero" if the number ends with a zero, but print "number" if it does not!
#!/bin/bash
/usr/bin/nawk '{
if ($1 ==/+0\b/){
print "Zero"}
else{
print "number"} (5 Replies)
hi,
i need my bash script to find regex in xml file.. and comment 2 lines before and after the line that contains regex.. can't use # needs to be <!-- at the beginning and --> and the end of the comment.
so eg..
first block
<filter>
<filter-name>MyRegEx</filter-name>
... (11 Replies)
I want to match the red portion:
9784323456787-Unknown Phrase with punctuation "Some other PhrASE."
Is this the best regex to match this?
'978\{10\}-*' (4 Replies)
I have a requirement - replace specified positions in a string with a character. I found perl regex useful for this approach. however, I am facing the following issue.
The target file 'temp' contains -
xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
The goal is to convert... (5 Replies)
Hi,
I have a file like this-
regex
1
2
regex
2
4
5
regex
4
6
8
regex
how do I split each interval to a new file? something like-
file1-1
2
file2-2 (7 Replies)
Hi Experts,
I am using ls with regex in the below manner:
VAR="*.txt *.TXT"
ls -l $VAR
This is working fine if I have both txt and TXT extension files in my directory. But if any of them is not present, its throwing errors, that *.TXT file not found in the directory. So what am i missing... (6 Replies)
Fairly straightforward, but I'm having an awful time getting what I thought was a simple regex to work. I'll give the command I was playing with, and I'm aware why this one doesn't work (the 1,3 is off the A-Z, not the whole expression), I just don't know what the fix is:
Actual Output(s):
$... (5 Replies)
I've been using the following regex below in a bash script on RHEL 5.5 using version
GNU bash, version 3.2.25(1)-release
I've tried using the script on RHEL 6.3 which uses GNU bash, version 4.1.2(1)-release
I assume there's been alot of changes to bash since that's quite a jump in revisions.... (12 Replies)