Shell Programming and Scripting

Hi there,
first post I really need advice. Before i managed my prob by reading your threads, very helpful so far!

Here is my prob:
I want to get an information out of a file with a huge amount of chars and numbers.
It´s like:

Code:

FGH= 12345  GHJ= 23456 ZUI= 78901 THB= 12345
BHU= 23456  JKL= 56789= THB= 56789 BHU= 6789

and this a thousand times

The information of interest is the number after "THB="
So I tried with

Code:

sed -n 's/.*\THB=   \([^ ]*\) .*$/\1/p' filename1 > filename2

This is half the way I have to go. bcoz if you take a closer look at line 1 in my example, you´ll recognize, that the THB is listed at the END of the line. Unfortunately my command only takes the information before the next blank... :/ so my result was

Code:

56789

How can I make my command copy the information if there either is a blank or the end of a row. No matter what is reached first? In order to get a result like:

Code:

12345
56789

Kind Regards

just remove space then..

Code:

sed -n 's/.*\THB= \([^ ]*\).*$/\1/p' file

12345
56789

Thank you for your reply. I edited my post above because I described my problem a tiny bit wrong. Anyway, i don´t get where i should remove space and how it should recognize the end of a line then.

see below.. spot the difference...(see red part)

Code:

$ cat file
FGH= 12345 GHJ= 23456 ZUI= 78901 THB= 12345
BHU= 23456 JKL= 56789= THB= 56789 BHU= 6789

$ sed -n 's/.*\THB= \([^ ]*\) .*$/\1/p' file
56789

$ sed -n 's/.*\THB= \([^ ]*\).*$/\1/p' file
12345
56789

Simply amazing! Thank you very much!