RE_COMP(3) Linux Programmer's Manual RE_COMP(3)NAME
re_comp, re_exec - BSD regex functions
SYNOPSIS
#define _REGEX_RE_COMP
#include <sys/types.h>
#include <regex.h>
char *re_comp(const char *regex);
int re_exec(const char *string);
DESCRIPTION
re_comp() is used to compile the null-terminated regular expression pointed to by regex. The compiled pattern occupies a static area, the
pattern buffer, which is overwritten by subsequent use of re_comp(). If regex is NULL, no operation is performed and the pattern buffer's
contents are not altered.
re_exec() is used to assess whether the null-terminated string pointed to by string matches the previously compiled regex.
RETURN VALUE
re_comp() returns NULL on successful compilation of regex otherwise it returns a pointer to an appropriate error message.
re_exec() returns 1 for a successful match, zero for failure.
ATTRIBUTES
For an explanation of the terms used in this section, see attributes(7).
+---------------------+---------------+-----------+
|Interface | Attribute | Value |
+---------------------+---------------+-----------+
|re_comp(), re_exec() | Thread safety | MT-Unsafe |
+---------------------+---------------+-----------+
CONFORMING TO
4.3BSD.
NOTES
These functions are obsolete; the functions documented in regcomp(3) should be used instead.
SEE ALSO regcomp(3), regex(7), GNU regex manual
COLOPHON
This page is part of release 4.15 of the Linux man-pages project. A description of the project, information about reporting bugs, and the
latest version of this page, can be found at https://www.kernel.org/doc/man-pages/.
GNU 2017-09-15 RE_COMP(3)
Check Out this Related Man Page
RE_COMP(3) Linux Programmer's Manual RE_COMP(3)NAME
re_comp, re_exec - BSD regex functions
SYNOPSIS
#define _REGEX_RE_COMP
#include <sys/types.h>
#include <regex.h>
char *re_comp(const char *regex);
int re_exec(const char *string);
DESCRIPTION
re_comp() is used to compile the null-terminated regular expression pointed to by regex. The compiled pattern occupies a static area, the
pattern buffer, which is overwritten by subsequent use of re_comp(). If regex is NULL, no operation is performed and the pattern buffer's
contents are not altered.
re_exec() is used to assess whether the null-terminated string pointed to by string matches the previously compiled regex.
RETURN VALUE
re_comp() returns NULL on successful compilation of regex otherwise it returns a pointer to an appropriate error message.
re_exec() returns 1 for a successful match, zero for failure.
ATTRIBUTES
For an explanation of the terms used in this section, see attributes(7).
+---------------------+---------------+-----------+
|Interface | Attribute | Value |
+---------------------+---------------+-----------+
|re_comp(), re_exec() | Thread safety | MT-Unsafe |
+---------------------+---------------+-----------+
CONFORMING TO
4.3BSD.
NOTES
These functions are obsolete; the functions documented in regcomp(3) should be used instead.
SEE ALSO regcomp(3), regex(7), GNU regex manual
COLOPHON
This page is part of release 4.15 of the Linux man-pages project. A description of the project, information about reporting bugs, and the
latest version of this page, can be found at https://www.kernel.org/doc/man-pages/.
GNU 2017-09-15 RE_COMP(3)
Hello!
I have problems with syntax...
I want a variable, that contains regex... is it possible?
Like $ a='.+->.+' and then use it in index ($0, "a").
I guess it won't work...
thank you :) (4 Replies)
Hi guys,
Pretty new to regex, and i know im doing something wrong here. I'm trying to get a regex command that restricts a string to be 8 characters long, and the first character cannot be 0. Here's what i have so far...
echo "01234" | grep "^{8}*$"
Thanks very much!
-Crawf
... (7 Replies)
Hi all
I am struggling to find out the capturing regex of a date format such as 10/12/2009. Also I need help on how to assign the date(i.e, 10/12/2009 ) to a variable after the match is found using the capturing regex.
Any help is appreciated. Thanks in advance. (5 Replies)
Need some help with a regex if loop problem.
File1:
2323
3232
4230
3230
4340
4343
233
32320
I want to print "Zero" if the number ends with a zero, but print "number" if it does not!
#!/bin/bash
/usr/bin/nawk '{
if ($1 ==/+0\b/){
print "Zero"}
else{
print "number"} (5 Replies)
I want to match the red portion:
9784323456787-Unknown Phrase with punctuation "Some other PhrASE."
Is this the best regex to match this?
'978\{10\}-*' (4 Replies)
Must be a bug or something. Whether I escape them or not, it will not work. No matter what I set the minimum and maximum to nothing gets caught. For instance:
find / -regex "/.{0, 50}.*" -maxdepth 1 or find / -regex "/.\{0, 50\}.*" -maxdepth 1 should pretty much catch everything residing within... (4 Replies)
I have a requirement - replace specified positions in a string with a character. I found perl regex useful for this approach. however, I am facing the following issue.
The target file 'temp' contains -
xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
The goal is to convert... (5 Replies)
Hi,
I have a file like this-
regex
1
2
regex
2
4
5
regex
4
6
8
regex
how do I split each interval to a new file? something like-
file1-1
2
file2-2 (7 Replies)
Hi Experts,
I am using ls with regex in the below manner:
VAR="*.txt *.TXT"
ls -l $VAR
This is working fine if I have both txt and TXT extension files in my directory. But if any of them is not present, its throwing errors, that *.TXT file not found in the directory. So what am i missing... (6 Replies)
I have a number of files that I pass through awk/gsub.
I believe to have found a working regex and on 'test bed' sites it matches, however within gsub it does not.
Examples:
Initial data:
/Volumes/Daniel/Public/Drop Box/_Hellsing_Ultimate_OVA_-_10_.mkv
gsub & regex:
gsub("\]+\]",""
... (4 Replies)
Hello,
I'm trying to get a quick help on regex since i'm not a regular programmer.
Below is the line i'm trying to apply my regex to..i want to use the regex in a for loop and this line will keep on changing.
subject=... (4 Replies)
Hello to all,
I'm trying to separate the string "str" using a regex within match function.
The substrings that I want to separate, begin with 22, 23, 24 or 25 and followed by 12 or 14 characters. And I want to
replace 22 with MJS, 23 with UYT, 24 with WER and 25 with PIL.
For this string... (4 Replies)
We have regex that we use to parse compliance policies in tripwire. can you please help to correct the regex :
policy is "Verify That Exported File Systems Specify the ro (read-only) Option"
the regex is
^.*-o+(?!ro+|ro\S+|\S+,ro\S+|\S+,ro+).*$
this does not work. how do we fix it ?
... (4 Replies)
Hello All,
While googling on regex I came across a site named Regulex Regulex:JavaScript Regular Expression Visualizer
I have written a simple regex ^(a|b|c)(*)@(.*) and could see its visualization; one could export it too, following is the screen shot.
... (3 Replies)