Shell Programming and Scripting

Folks,

I have a textfile with the config of my router. Part of that config looks like this:

router config
...
ip access-list extended MyAccessList
remark this is my security rule
permit host 10.0.0.1 any
deny host 10.0.0.2 any
...
ip access-list extended YourAccessList
remark this is your security rule
permit host 192.168.0.1 any
deny host 192.168.0.2 any
...
router config
...

I want to script something that shows MyAccessList and all related entries (starting with remark/permit/deny).

So this should be the output:

ip access-list extended MyAccessList
remark this is my security rule
permit host 10.0.0.1 any
deny host 10.0.0.2 any
...

I have been thinking about combining grep and awk and a couple of other paths, but I don't even get close

Anyone an idea how to start something like this?

Much appreciated,

Philipz

You can simply do something like:

Code:

awk '/MyAccessList$/{
  print;getline
  print;getline
  print;getline
  print;exit
}' file

Regards

Another one and shorter:

Code:

awk '/MyAccessList$/{f=4}f{print;f--}' file

Regards

You can also use sed this way so that if the number of lines following the line containing MyAccessList is unknown, they will all get printed until you hit the line containing YourAccessList:

sed -n '/MyAccessList/,/YourAccessList/{/YourAccessList/d;p;}' file

Hope this helps.

... a bit shorter:

Code:

awk '/^ip access-list extended/ {f=4}f--' myFile

vgersh99,

This prints unwanted lines if f becomes negative.

Regards

.. too short
Let's sed

Code:

sed -n 'N;N;N;/My/p' file