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05-07-2008
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word substitution in unix
Hi I am trying to substitute 2 words on the same line with _S02 as suffix. Like this .
IN "TSOPS09" INDEX IN "TSOPIX09" ; to IN "TSOPS09_S02" INDEX IN "TSOPIX09_S02" ; i used the following code to make the change , it works fine for first substitution not the second one . TBLSP_NM=` cat db2look_FACT_PHYSICIAN.ddl | grep -i TSOP | awk '{print $2}' | cut -d '"' -f 2 ` echo $TBLSP_NM sed -e 's/'${TBLSP_NM}'/'${TBLSP_NM}'_S02/g' db2look_FACT_PHYSICIAN.ddl the output comes as IN "TSOPS09_S02" INDEX IN "TSOPIX09" ; Any help is appreciated ! 
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05-07-2008
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vgersh preceded me, anyway another one:
Code:
sed 's/\(TSOP[^"]*\)/\1_S02/g' db2look_FACT_PHYSICIAN.ddl
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05-07-2008
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Hi,
I ahve next question . I have script which gets info from db2 engine. The script is cat sample_substitute.sh CNTR_NM=`db2 -x "select CONTAINER_NAME ,usable_pages from table( SNAPSHOT_CONTAINER('TST103',-1)) as SNAPSHOT_CONTAINER, syscat.tablespaces where tablespace_name = tbspace and tbspacetype = 'D' and tbspace='TSOPS06'" ` echo ${CNTR_NM} The output is like this /dmpath/dmtiadm1/db2fs1p00/tsops06 2128 But I am trying to get the output like this '/dmpath/dmtiadm1/db2fs1p00/tsops06' 2128 i.e. the string inside the single quote. Thanks again in advance !
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05-08-2008
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You may use a thing like:
Code:
echo "${CNTR_NM}" | sed "s/\([^ ]*\)/'\1'/1"
Code:
echo "${CNTR_NM}" | awk '{ printf("\047%s\047 %s\n", $1, $2) }'
On Solaris, use nawk instead of awk.
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