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05-22-2008
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extract field of characters after a specific pattern - using UNIX shell script
Hello,
Below is my input file's content ( in HP-UX platform ): ABCD120672-B21 1 ABCD142257-002 1 ABCD142257-003 1 ABCD142257-006 1 From the above, I just want to get the field of 13 characters that comes after 'ABCD' i.e '120672-B21'... . Could you please let me know the shell script that I have to use? Thanks 
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05-22-2008
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Try this:
Code:
sed 's/ABCD\(.*\) .*/\1/' file > newfile
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