Why to put $ ???
More over hope u remember the point "script works fine when executed manually" ....

My script is just as follows:

#!/usr/bin/sh

ZIPFILE_PATH=/...
MYLOCATION=/...

cd MYLOCATION

unzip $ZIPFILE

FILECOUNT=`ls -l | wc -l`

if [ $FILECOUNT -eq 7 ]
then
do some process
else
send an error mail


So for me, when i schedule the above script in CROn, always i do get the error mail. If i run it manually then "do some process" is happening.

what can be done ???

Shouldn't the unzip command read:

unzip $ZIPFILE_PATH # here I am assuming that the ZIPFILE_PATH holds the entire path, including the filename.

I don't see you setting $ZIPFILE anywhere in the script.

As previously said , you just need to load your login profile (.profile, .login or whatever it is) for the cron to mimic the environment you are in when you're on the shell, try that and everything should be ok.

hi blowtorch,

its was a samll mistake while typing here...

its not $ZIPFILE ..
it should be

unzip $ZIPFILE_PATH

hi andryk,
loading my .profile means ... i dont get you .. just executing that file or not clear .. but one thing . simple jobs scheduled in cron is working fine ..

I want to add one more point here ..

when i gave :
$whereis unzip , its showing

unzip :

So i think its not able to find the location of the unzip command.. Could this be the reason why cron is not able to execute the unzip command ??

Yes, the way of loading your profile in your batch is '. $HOME/.profile', there's a space between the dot and the $ (without the quote of course )

Maybe, you may want to search for it: find /usr -name unzip -print or even from the root.

Good luck.

Hi andryk,
Great .. thanks a lot .. its working ... But i want to know the reason behind this ... what is the necessity to run the .profile file ?? Kindly give me an explanation ..

Thank u so much once again ..