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HP-UX HP-UX (Hewlett Packard UniX) is Hewlett-Packard's proprietary implementation of the Unix operating system, based on System V.

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  #8  
Old 03-26-2008
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Join Date: Mar 2008
Posts: 7
Quote:
Originally Posted by biswagit View Post
$ who -u | grep 'jarhadta'
jarhadta pts/2 Mar 26 15:46 1:15 18639 10.236.0.207
jarhadta pts/22 Feb 15 00:50 old 9540 10.236.0.207
jarhadta pts/23 Feb 15 00:50 old 9572 10.236.0.207
jarhadta pts/24 Feb 15 00:50 old 9616 10.236.0.207
jarhadta pts/25 Feb 15 00:50 old 9650 10.236.0.207
jarhadta pts/26 Feb 15 00:50 old 9690 10.236.0.207
jarhadta pts/27 Feb 15 00:50 old 9728 10.236.0.207
jarhadta pts/28 Feb 15 00:50 old 9761 10.236.0.207
jarhadta pts/29 Feb 15 00:50 old 9815 10.236.0.207
jarhadta pts/30 Feb 15 00:51 old 10056 10.236.0.207
jarhadta pts/31 Feb 15 00:51 old 10088 10.236.0.207
jarhadta pts/33 Feb 15 00:51 old 9954 10.236.0.207
jarhadta pts/32 Feb 15 00:51 old 9933 10.236.0.207
jarhadta pts/34 Feb 15 00:51 old 9992 10.236.0.207
jarhadta pts/36 Feb 15 00:51 old 10122 10.236.0.207
jarhadta pts/35 Feb 15 00:51 old 10024 10.236.0.207
jarhadta pts/37 Feb 15 00:51 old 10156 10.236.0.207


Please tell me how can i kill this user 'jarhadta' which are in old status.
if any one can help me pls mail me the solution to my email address bishu_1312@hotmail.com
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  #9  
Old 03-26-2008
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Join Date: Jul 2007
Posts: 93
Code:
who -u | grep 'jarhadta' | awk '$6=/old/{ print $7}' | xargs kill -HUP
Note, substitute the echo command for kill first to test it gives the processes you're looking for.
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  #10  
Old 03-27-2008
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Join Date: Mar 2008
Posts: 7
I cannt understand what to do. please give me a detail command using my report.


Quote:
Originally Posted by denn View Post
Code:
who -u | grep 'jarhadta' | awk '$6=/old/{ print $7}' | xargs kill -HUP
Note, substitute the echo command for kill first to test it gives the processes you're looking for.
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  #11  
Old 03-27-2008
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Join Date: Mar 2008
Posts: 7
hi
"awk '$6=/old/{ print $7}' | xargs kill -HUP" i dont understand this. please give me the solution based on my report


Quote:
Originally Posted by denn View Post
Code:
who -u | grep 'jarhadta' | awk '$6=/old/{ print $7}' | xargs kill -HUP
Note, substitute the echo command for kill first to test it gives the processes you're looking for.
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  #12  
Old 03-28-2008
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Join Date: Jul 2007
Posts: 93
Did you try the command, and if so what was the results?

You have to use the full command posted, in my original post, not just:
"awk '$6=/old/{ print $7}' | xargs kill -HUP"

run the below, and it should give all the process ID's you want to kill, if
not please post results.
Code:
who -u | grep 'jarhadta' | awk '$6=/old/{ print $7}'
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  #13  
Old 03-28-2008
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Join Date: Mar 2008
Posts: 7
hi
thanks. when i gave this command then i got process id and then when i want to kill that old process by using kill -9 PID(process id) then it shows no such process. It should be noted that 'jarhadta' is a ldap user. please resolve it for me.

Quote:
Originally Posted by denn View Post
Did you try the command, and if so what was the results?

You have to use the full command posted, in my original post, not just:
"awk '$6=/old/{ print $7}' | xargs kill -HUP"

run the below, and it should give all the process ID's you want to kill, if
not please post results.
Code:
who -u | grep 'jarhadta' | awk '$6=/old/{ print $7}'
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  #14  
Old 03-31-2008
Registered User
  

Join Date: Mar 2008
Posts: 7
hi,
Any one here who can help me in this issue. please help me

Quote:
Originally Posted by biswagit View Post
hi
thanks. when i gave this command then i got process id and then when i want to kill that old process by using kill -9 PID(process id) then it shows no such process. It should be noted that 'jarhadta' is a ldap user. please resolve it for me.
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