syntax error The source line is 1.
The error context is
($5 ~ "$(date >>> "+% <<< b")") && ($6 <= "$(echo $(date "+%e") - 5 | bc)")
awk: There is an extra ) character.
awk: Quitting
The source line is 1.
ps -ef | perl -MDate::Calc -e 'while(<>){print "$1\t:\t$2\n" if ((/^\s+\w+\s+(\d+)\s+\d+\s+\d+\s+(\w{3}\s+\d+|20\d+|\d{2}:\d{2}:\d{2})/)&&(more_recent($2,3)))}'
writing the more_recent routine is left as a rather complex exercise The regex above will capture the following time stamp styles in $2
16:45:00
Feb 08
2011
Your more_recent routine would have to deal with that (The first is obviously today's the last obviously later so only the middle style requires the use of the Date::Calc module.
ps -ef | perl -MDate::Calc -e 'while(<>){print "$1\t:\t$2\n" if ((/^\s+\w+\s+(\d+)\s+\d+\s+\d+\s+(\w{3}\s+\d+|20\d+|\d{2}:\d{2}:\d{2})/)&&(more_recent($2,3)))}'
writing the more_recent routine is left as a rather complex exercise The regex above will capture the following time stamp styles in $2
16:45:00
Feb 08
2011
Your more_recent routine would have to deal with that (The first is obviously today's the last obviously later so only the middle style requires the use of the Date::Calc module.
Thank you .. just starting to learn Perl so not sure what you are refering to ..
Another approach (skeleton). Start with "UNIX95= ps -af" to eliminate most of the system processes, then eliminate anything dated today and positively select lines containing a hyphen (which comes from changed format of "etime" greater than one day).
One side effect is that this pick up "defunct" processes (which display in the old "ps" as uid -3), but they might be interesting anyway.
Avoided outputting the "args" option because it could contain hyphens.
If you need to output the process line in new "ps" format then we can extend the pipeline to pick up the PID ($2) and feed it to "ps -fp<pid>", eliminate "defunct", and then feed the list to a less-complicated "awk" because all the dates will be in the same format. No need to do "ps -ef" for every individual process.
Afterthought: The UNIX95 "ps" etime field contains the number of days old. This might be simple.
Another approach (skeleton). Start with "UNIX95= ps -af" to eliminate most of the system processes, then eliminate anything dated today and positively select lines containing a hyphen (which comes from changed format of "etime" greater than one day).
One side effect is that this pick up "defunct" processes (which display in the old "ps" as uid -3), but they might be interesting anyway.
Avoided outputting the "args" option because it could contain hyphens.
If you need to output the process line in new "ps" format then we can extend the pipeline to pick up the PID ($2) and feed it to "ps -fp<pid>", eliminate "defunct", and then feed the list to a less-complicated "awk" because all the dates will be in the same format. No need to do "ps -ef" for every individual process.
Afterthought: The UNIX95 "ps" etime field contains the number of days old. This might be simple.
Thank you very much !!
Finally got it working.. added following filters for user procs older 5 days in this case.
@delphys
I'm no awk expert but this has inspired me to learn. If awk can take the leading numeric character(s) of a complex alphanumeric string (like the format of "etime" from a Berkeley "ps") into a numeric comparison awk '$5 >= "5"' that is really useful.
Personally I'd would have had to extract the leading numbers (i.e. the number of idle days) and used a Shell integer comparison.
I would have coded the check for greater than 5 days differently. At least with the version of awk I've got installed in various places, your code doesn't work. Here is the output using your ps command from one of my boxes:
When I pipe that through your awk ($5 > "5") the output is this:
Code:
USER PID PPID CPU ELAPSED STIME
scooter 20422 20420 - 9-21:03:52 Jan29
which as far as I can tell is wrong. It should have listed all of the processes that are shown as being 12 days old in addition to the one that it did list.
The problem is that you are doing string comparison, instead of doing numeric comparison and a string which begins with a '1' is less than a string that begins with a '5'.
I make a habit of always 'casting' fields to force them to be numeric before doing any kind of numeric comparison with them. I've been bitten countless times by forgetting this. To fix the problem, change your awk:
Code:
awk ' $5+0 > 5'
Notice that there are no quotes round the 5, and that +0 causes the fifth field to be converted to integer before doing the comparison. A string like 12-20:31:50 becomes an integer 12 when 0 is added to it, and the comparison yields the expected result. With the changes:
You should also notice the change to the grep that avoids picking up a record for a process active less than 24 hours (it matched the dash in the cpu column, and the change forces it to match a dash only between two numbers as would appear in the date column.) You can also eliminate the grep completely:
Hi,
Could someone help me that what the problem is in this code?
#!/bin/sh
FOLDER=/abc/datasource/checkstatus
TIMESTAMP=$(date +%s)
for filename in $(find $FOLDER -maxdepth 1 -type f -name "CHECK_STATUS*"); do
f1=$($filename -Eo "{4}+")
f2=$(date -d "$f1" +%s)
if... (11 Replies)
Hi All,
I am new to the scripting and using solaris 10 OS. Please suggest me from the below script which modifications need to be done to delete the files more that 2days older. Current script is deleting existing file.
# Remove old explorer runs if needed
DIR=`dirname ${EXP_TARGET}`
if ... (2 Replies)
Hi All,
OS :- HP-UX wm5qa B.11.23 U ia64 1119805695 unlimited-user license
I need to search files older than 50 days. I've used following command in order to search desired files, I also discoverd, it's showing today's files as well. Do you have any clue with this ?
wmqa1> find .... (4 Replies)
Hi All,
I am trying to automate some stuff to make my 'to-do-things' easier. I am in need for help regarding this.
I have an output
root 17187 3465 0 23:00:00 ? 0:01 Process1
root 4975 4974 0 May 12 ? 0:00 Process2
root 4042 16713 0 Jan 30 pts/22 0:00... (4 Replies)
Dear all,
i use incremental backup my data with .zip to my hard drive. what i need is i don't want the old .zip file older than 30 days. how to write a shell script automatically remove my external hard disc zip backup folders older than 30 days?
Regards, (2 Replies)
Hi, I need a .ksh script that lists all the process that are currently running and older than 3 days. once the process list is available i need to mail the list and then kill those processes.
Quick response is highly appreciated :b:
Thanks in Advance!!!
Sri (3 Replies)
Hi all,
I want to delete log files with extension .log which are older than 30
days. How to delete those files?
Operating system -- Sun solaris 10
Your input is highly appreciated.
Thanks in advance.
Regards,
Williams (2 Replies)
I will like to write a script that delete all files that are older than 7 days in a directory and it's subdirectories. Can any one help me out witht the magic command or script?
Thanks in advance,
Odogboly98:confused: (3 Replies)
02-08-2012
The regex above will capture the following time stamp styles in $2