I have the following piece of codes. Please explain it to me in great detail how are these codes working.

1. #include <stdio.h>
int main(){
int x;
x=0;
while (x<2 && fork()){
if (!fork()) execlp("echo","x++","x",0);
x++;
system("echo x+x");
}
}

2.

#include <stdio.h>
int i;
int main() {
for(i=0;i<2;i++){
if(fork())
fork();
}
printf ("%d\n", i);
system(("echo i++");
}


The attempts at a solution (include all code and scripts):[/B]
Output of 1:
x
x+x
x+x
x


Output of 2:
2
i++
2
i++
2
i++
2
i++
2
i++
2
i++
2
i++
2
2
i++
i++




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