Homework & Coursework Questions

$ while read line; do if [[ ${#line} > 10 && ${#line} != 0 ]]; then echo ${#line}; fi; done <inputfile 
9
5
21
14
90

if [[ ${#line} -gt $maxline && ${#line} != 0 ]]

./linelengthhw2vs2.sh: line 34: -r: command not found

$ cat testfile
123
      <- here are 5 spaces
abcde
aaaaaaaaa
   <- here are 2 spaces
aaaaaa
$ cat testfile | ./linelength.sh 
line either blank or between max or min
line either blank or between max or min
The longest line is 9 characters line:  4 contents aaaaaaaaa
The shortest line is 6 characters line:  6 contents aaaaaa
$

      -x  Print commands and their arguments as they are executed

$ cat testfile | ./linelength.sh 
+ linecount=1
+ maxlinechars=0
+ minlinechars=0
+ maxcontents=0
+ mincontents=0
+ maxlinenumber=0
+ minlinenumber=0
+ IFS=
+ read -r line
+ line=123
+ ((  3 > 0  ))
+ maxlinechars=3           #
+ maxcontents=123          # OK, you stored the values for the first string as longest string. So far, so good.
+ maxlinenumber=1          #
+ (( linecount++ ))
+ IFS=
+ read -r line
+ line=
+ ((  0 > 3  ))
+ ((  0 == 0 && 0 != 0  ))
+ ((  0 < 0 && 0 != 0  ))
+ echo line either blank or between max or min
line either blank or between max or min
+ (( linecount++ ))
+ IFS=
+ read -r line
+ line=abcde
+ ((  5 > 3  ))
+ maxlinechars=5           # Next line is longer than the previous one...
+ maxcontents=abcde        # At this moment, line number 1 has the shortest string, but that's somehow ignored here
+ maxlinenumber=3          # and leads to an incorrect report at the end.
+ (( linecount++ ))
...