Note: Without school/professor/course information, you will be banned if you post here! You must complete the entire template (not just parts of it).
I'm totally lost on what the code suppose to look like on this project:
The Antonio Czechos Drywall Firm has hired you to help implement a directory structure for them based on Figure 5-19. Because you were called out of town to aid another customer, you cannot go to the site. In the meantime, you decide to write a script that will create the structure for them. To create the directory structure, complete the following tasks:
Helllllllllllllllllllllllp!!!
---------- Post updated at 01:12 PM ---------- Previous update was at 12:42 PM ----------
So this the code I wrote completely but i believe it's wrong
Code:
!/bin/bash
if [ ! -d /home/AC_Drywall]
then
echo no directory
then
mkdir -p /home/AC_Drywall
elif [ ! -d ]; then
echo "$dir already exist"
fi
if [ ! -d /home/AC_Drywall/MIS/Production/Marketing]
then
echo no directory
then
mkdir -p /home/AC_Drywall/MIS/Production/Marketing
elif [ ! -d ]; then
echo "dir already exist"
fi
if [ ! -d /home/AC_Drywall/MIS/Project1/work1.doc/work2.doc]
then
echo no directory
then
mkdir -p /home/AC_Drywall/MIS/Project1/work1.doc/work2.doc
elif [ ! -d ]; then
echo "dir already exist"
fi
if [ ! -d /home/AC_Drywall/Production/Shift1/Shift2/Shift3]
then
echo no directory
then
mkdir -p /home/AC_Drywall/Production/Shift1/Shift2/Shift3
elif [ ! -d ]; then
echo "dir already exist"
fi
if [ ! -d /home/AC_Drywall/Production/Shift1/.manager1.txt/emp1.txt]
then
echo no directory
then
mkdir -p /home/AC_Drywall/Production/Shift1/.manager1.txt/emp1.txt
elif [ ! -d ]; then
echo "dir already exist"
fi
if [ ! -d /home/AC_Drywall/Marketing/Sales/Admin]
then
echo no directory
then
mkdir -p /home/AC_Drywall/Marketing/Sales/Admin
elif [ ! -d ]; then
echo "dir already exist"
fi
if [ ! -d /home/AC_Drywall/Marketing/Sales/East/West]
then
echo no directory
then
mkdir -p /home/AC_Drywall/Marketing/Sales/East/West
elif [ ! -d ]; then
echo "dir already exist"
fi
Adding "helllllllllllllp!!!!11/1/1./1one" to a post never helps. Don't do it.
Since you're using mkdir -p, you don't need to check if a directory already exists. It will work fine if it does already, and return error if it can't make any of the directories. Much less repetition.
Code:
if ! mkdir -p /path/to/dir1 /path/to/dir2 /path/to/dir3 /path/to/dir4 ...
then
echo "Couldn't create directories"
exit 1
fi
Thx Corona688
I'm extremely new to the script writing and just don't get it but I'm putting it together. I understand the "echo "dir already exist" thx I will make that change. But i'm not understanding the "exit 1"
An are you saying I could've wrote
Code:
if ! -d /home/AC_Drywall/MIS/Production/Marketing /home/AC_Drywall/MIS/Project1/......
all on one line and it would've created all of them with out doing it over and over again.
Last edited by Scrutinizer; 04-09-2013 at 02:34 PM..
Reason: code tags
Thx Corona688
I'm extremely new to the script writing and just don't get it but I'm putting it together. I understand the "echo "dir already exist" thx I will make that change.
I don't know what you're talking about, I didn't mention that.
Quote:
But i'm not understanding the "exit 1"
It means, quit the script early with an error code. All programs return a number when they quit. Zero means success. Nonzero means failure of some sort. 'if' statements use these codes.
Quote:
An are you saying I could've wrote
if ! -d /home/AC_Drywall/MIS/Production/Marketing /home/AC_Drywall/MIS/Project1/...... all on one line and it would've created all of them with out doing it over and over again.
No, I'm saying you could've done:
Code:
if ! mkdir -p /path/to/dir1 /path/to/dir2 /path/to/dir3 /path/to/dir4 ...
then
echo "Couldn't create directories"
exit 1
fi
...and it would create them all without going through it over and over again.
You don't need -d at all. mkdir -p checks for you.
You can put any command in an if-statement, mkdir included. Any command returns an error code.
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04-09-2013
