Homework & Coursework Questions

I am trying to create a Unix script that when ran will provide a veiw of the files of the week that the user inputs, I have this one down. Then I would like them to be able to type in one of the files that is in that week and it displays that file. The script that I have keeps looping the week number until I hit q for quit and then it asks the user the name of the file they want to view, but does not display the contents. Some help would be appreciated. Thank you.

Course: POS 420/University of Phoenix

Code that I have been working with:

Code:

echo author : Goob
date

echo "Please enter week number (1-3) or q to quit"
read num

while test $num ! =q
do

       if [ $num -lt 4 ]
          then echo "The files submitted in week $num are:"
                     ls /mnt/sdb1/week$num/file*
          else echo "Incorrect week number!"

fi

echo "Please enter file name from chosen week"
read file

while test $file != q
do

      if [ -f /mnt/sdb1/week$num/$file ]
      then echo "The contents of file $file are:"
          cat /mnt/sdb1/week$num/$file
          break
      else read -p "Incorrect file name! Please select again or enter q:" file

fi

done

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Thank You.

The UNIX and Linux Forums

Hi.

Does the script output an error?

Question: In your first while loop, you write "ls /mnt/sdb1/week$num/file*"

Is the user expected to type "file" as part of the filename?

i.e. your cat in the second while is "cat /mnt/sdb1/week$num/$file"

So to see file "whatever", I'd have to type "filewhatever".

If the file is not being displayed, either there is an error, or the follow on prompt "Incorrect filename ... Please select again.... " would be given. Is it?

is the following a typo in this forum, or is this the code as you wrote it?

Code:

while test $num ! =q

there's an inversion (of nothing really) followed by the equal to operator.

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Thank You.

The UNIX and Linux Forums.