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Old 04-28-2008
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What is the difference between f(...), f(void) and f()

What is the difference between f(...) , f(void),f()
I know that f(void) doesn't take any parameters, but what about f() and f(...) Does the last call of function even exists?
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Old 04-28-2008
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Quote:
Originally Posted by purplelightspar View Post
What is the difference between f(...) , f(void),f()
I know that f(void) doesn't take any parameters, but what about f() and f(...) Does the last call of function even exists?
f(void) means that the function does not take any arguments.
f() and f(void) are synonymous since f() is the K&R C equivalent of the ANSI C f(void).
f(...) means that the function takes a variable length argument list
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Old 04-29-2008
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C99 is different from K&R foo() essentially means it takes undefined arguments.
cc -Ae means compile according to strict ANSI C99 standards..
Code:
csadev:/home/jmcnama> cc -Ae foo.c
csadev:/home/jmcnama> a.out
you found foo
you found foo
you found foo
you found foo
csadev:/home/jmcnama> lint foo.c


==============
name declared but never used or defined
    __bufendtab         stdio.h(744)
    errno       errno.h(39)
    ___sysconf          signal.h(207)
    __nl_char_size      stdlib.h(79)
    sigwait     signal.h(232)
    pthread_sigmask     signal.h(234)
    pthread_kill        signal.h(235)
    getdate_err         time.h(741)
    __iob       stdio.h(174)
function used with a variable number of arguments
    foo         foo.c(4) :: foo.c(12)
    foo         foo.c(4) :: foo.c(13)
    foo         foo.c(4) :: foo.c(14)
function returns value which is sometimes ignored
    foo
It fails to lint which should be a big clue this is bad.

Here is the code:
Code:
/* C99-(semi)compliant but perverse coding */
#include <stdlib.h>

int foo()
{
	return printf("you found foo\n");
}

int main()
{
	foo();
	foo(2);
	foo("hi there");
	return foo("this code stinks");
}
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