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10-24-2008
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Does this work for you?
Code:
> ls -l
total 16
drwxrwx--- 2 xxx dp 512 Oct 24 08:56 ./
drwxrwx--- 99 xxx dp 3072 Oct 24 08:48 ../
-rw-rw---- 1 xxx dp 0 Oct 24 08:53 LG_JG_CLIENT_20081024114245_1.txt
-rw-rw---- 1 xxx dp 0 Oct 24 08:56 LG_JG_CLIENT_200810241142_1.txt
-rw-rw---- 1 xxx dp 0 Oct 24 08:55 LG_JG_CLIENT_baddata.txt
-rw-rw---- 1 xxx dp 0 Oct 24 08:49 LG_JG_CUSTOMER_20081024114245.txt
-rw-rw---- 1 xxx dp 0 Oct 24 08:49 LG_JG_CUSTOMER_20081024114245_1.txt
-rw-rw---- 1 xxx dp 0 Oct 24 08:49 LM_CM_CUSTOMER_20081024114245_2.txt
-rw-rw---- 1 xxx dp 0 Oct 24 08:48 LM_CM_TELEPHONE_20081024114245_1.txt
-rw-rw---- 1 xxx dp 0 Oct 24 08:48 LM_CM_TELEPHONE_20081024114245_2.txt
-rw-rw---- 1 xxx dp 0 Oct 24 08:48 LM_CM_TELEPHONE_20081024114269_3.txt
-rw-rw---- 1 xxx dp 0 Oct 24 08:49 LM_JG_CUSTOMER_20081024114245_1.txt
> ls -l | grep "[A-Z]*_[A-Z]*_[A-Z]*_[0-9]\{14\}*_[0-9]*.txt"
-rw-rw---- 1 xxx dp 0 Oct 24 08:53 LG_JG_CLIENT_20081024114245_1.txt
-rw-rw---- 1 xxx dp 0 Oct 24 08:49 LG_JG_CUSTOMER_20081024114245_1.txt
-rw-rw---- 1 xxx dp 0 Oct 24 08:49 LM_CM_CUSTOMER_20081024114245_2.txt
-rw-rw---- 1 xxx dp 0 Oct 24 08:48 LM_CM_TELEPHONE_20081024114245_1.txt
-rw-rw---- 1 xxx dp 0 Oct 24 08:48 LM_CM_TELEPHONE_20081024114245_2.txt
-rw-rw---- 1 xxx dp 0 Oct 24 08:48 LM_CM_TELEPHONE_20081024114269_3.txt
-rw-rw---- 1 xxx dp 0 Oct 24 08:49 LM_JG_CUSTOMER_20081024114245_1.txt
>
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10-24-2008
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Quote:
Code:
print $KSH_VERSION If you get no output, you have ksh88. If you insist to know the exact release of ksh88  set -o vi (or other) -> Esc (to enter in command mode) -> Ctrl+V: Code:
$ set -o vi $ Version M-11/16/88i |
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10-24-2008
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Here is an approach with awk
Code:
> ls -w1
./
../
LG_JG_CLIENT_20081024114245_1.txt
LG_JG_CLIENT_200810241142_1.txt
LG_JG_CLIENT_baddata.txt
LG_JG_CUSTOMER_20081024114245.txt
LG_JG_CUSTOMER_20081024114245_1.txt
LM_CM_CUSTOMER_20081024114245_2.txt
LM_CM_TELEPHONE_20081024114245_1.txt
LM_CM_TELEPHONE_20081024114245_2.txt
LM_CM_TELEPHONE_20081024114269_3.txt
LM_JG_CUSTOMER_20081024114245_1.txt
> ls | awk -F"_" 'NF==5 && ($3=="CLIENT" || $3=="CUSTOMER") {print $0}'
LG_JG_CLIENT_20081024114245_1.txt
LG_JG_CLIENT_200810241142_1.txt
LG_JG_CUSTOMER_20081024114245_1.txt
LM_CM_CUSTOMER_20081024114245_2.txt
LM_JG_CUSTOMER_20081024114245_1.txt
> ls | awk -F"_" 'NF==5 && ($3=="CLIENT" || $3=="CUSTOMER") && ($4>20080101000000) {print $0}'
LG_JG_CLIENT_20081024114245_1.txt
LG_JG_CUSTOMER_20081024114245_1.txt
LM_CM_CUSTOMER_20081024114245_2.txt
LM_JG_CUSTOMER_20081024114245_1.txt
Perhaps you can see/understand the logic used here, and expand upon it for your needs. I make sure five fields -- four _ characters I see if field 3 is CLIENT or CUSTOMER I verify that the date > 2080101 (date) 000000 (time) |
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10-24-2008
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Yes, something like this, thanks.
1.Should it be just "ls" instead of "ls -l"? 2.How to check if "object" is in the list? 3. what is the right syntax to put some params into grep, like ls | grep "${VENDOR}_${SOURCE}_[A-Z]*_[0-9]\{14\}*_[0-9]*.txt" ??? Go Celts! Last edited by Leo_NN; 10-24-2008 at 01:16 PM.. |
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