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Old 03-12-2009
nuvpal nuvpal is offline
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Join Date: Mar 2009
Posts: 7
Function Recursion Shift Problem

Hi, I'm trying to create a script that will display the contents of the users directories, but i'm confused about how to incorporate the shift properly.

The problem I'm getting with my script is that it goes throught the first couple of directories but then returns an error as it loses the first directory when continuing the search to other directories (I hope that makes sense?!)
EDIT: I apologise, that was the old problem, now the problem is the path to be searched adds the wrong directories so it looks in paths that do not exist

Here's my code, any help would be greatly appreciated.


Code:
direc=~
list=$(ls -l $direc | egrep '^d' | cut -d" " -f8)
function printList() {
        for line in $*
        do
                echo $line
                list=$(ls -l $direc/$1 | egrep '^d' | cut -d" " -f8)
                direc=$direc/$1
                shift
                printList $list
 
        done
}
printList $list

EDIT2: I have also tried suppressing the error returned by the ls to dev null by editing the line inside the function:

Code:
                list=$(ls -l $direc/$1 | egrep '^d' | cut -d" " -f8 2>/dev/null)

and also

Code:
                list=$(ls -l $direc/$1 | egrep '^d' | cut -d" " -f8) 2>/dev/null

but niether work, both return the same output, in other words they are still not suppressesing the standard error.

Last edited by nuvpal; 03-12-2009 at 06:22 AM..
 

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