Hello-

I'm trying to write a find command that will exclude certain directories to speed up the find and search the rest of the directory structure to list any files that contain the specified values listed in my egrep.

Specifically, I want the command below to search the current directory and all sub-directories EXCEPT for the "log" and "out" directories and give me a list of file names that contain "sun1216, sun1586, sun1153, PRIVIS1, PRIVIS2". I expected the command below to do the trick but it appears to not work.

find . -follow \( -name "log" -o -name "out" \)
-prune | xargs egrep -li "sun1216|sun1586|sun1153|PRIVIS1|PRIVIS2"

Any suggestions on what's wrong?
Any suggestion on using exec versus xargs?

Thanks

I apologize, the syntax is:

find . -follow \( -name "log" -o -name "out" \)
-prune -o -print | xargs
egrep -li "sun1216|sun1586|sun1153|PRIVIS1|PRIVIS2"

No suggestions?

find . -follow \( -name "log" -o -name "out" \) -prune -o -print | egrep -li "sun1216|sun1586|sun1153|PRIVIS1|PRIVIS2"
that is, remove the xargs from your final syntax

The command you provided does not appear to work. It returns nothing? I'm currently testing this:

find . -follow -type d \( -name log -o -name out \) -prune -o -type f
-exec egrep -li 'sun1216|sun1586|sun1153|PRIVIS1|PRIVIS2' {} \;

Any more suggestions? Thanks for the feedback.

That is the wrong command. Try the one I posted.