Need help in inserting a value.........

santyshyam · #1 (**permalink**) 08-05-2008

Hello,

I'm having a files with variable no of lines. An example for this file is as follows

~xxx
STRT 0.0000000000 :
STOP :
~xxxxx
0.000000 557.109552 -557.109552
1511.482910 -954.373377 954.373377

in the STOP line below the 0.00000000000 I need the first coloumn of the last line ie in this case 1511.482910. In each file the value will be changing.
I'm having more than 500 of such files.
I believe a shell script or awk can handle this. Please help me.

cfajohnson · #2 (**permalink**) 08-05-2008

If the line you want is the last line of the file:

Code:
tail -n1 "$FILE" | cut -f1

santyshyam · #3 (**permalink**) 08-05-2008

Quote:

Originally Posted by cfajohnson

If the line you want is the last line of the file:

Code:
tail -n1 "$FILE" | cut -f1

If not, how do you determine which line you want?

for finding out the value of the last line's first coloumn I will use
awk '{field = $1 }; END {print field}' filename
but my need is to print this value next to STOP.

Annihilannic · #4 (**permalink**) 08-05-2008

Do you mean like this?

Code:

awk '{field = $1 }; END {print "STOP",field}' filename

summer_cherry · #5 (**permalink**) 08-05-2008

hope below one can help, it suppose all your files are named with .txt suffix.

Code:

for i in `ls *.txt`
do
	val=`cat $i | tail -1 | awk '{print $1}'`
	nawk -v val="$val" '{
		if(index($0,"STOP")!=0)
			print $0"  "val
		else
			print
	}' $i
done

buffoonix · #6 (**permalink**) 08-05-2008

It would have been easier for willing repliers
if you had provided us with line numbers so that it gets conspicuous what characters still belong to the same line.
This is rather ambiguous

Quote:

in the STOP line below the 0.00000000000 I need the first coloumn of the last line

Depending whatever you consider a valid field separator for this file
if it really is in the same STOP line,
it should be as simple as e.g.

Code:

$ awk -F' : ' '$1~/^STOP/{print$2}' file_to_parse

cfajohnson · #7 (**permalink**) 08-05-2008

Quote:

Originally Posted by santyshyam

for finding out the value of the last line's first coloumn I will use
awk '{field = $1 }; END {print field}' filename
but my need is to print this value next to STOP.

You haven't answered the question: How do you determine which line contains the value?

In the example you gave, that line is not "next to STOP".

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