![]() |
Hello and Welcome from United States to the UNIX and Linux Forums! Thank You for Visiting and Joining Our Global Community.
|
|
google unix.com
|
|||||||
| Forums | Register | Forum Rules | Links | Albums | FAQ | Members List | Calendar | Search | Today's Posts | Mark Forums Read |
| Shell Programming and Scripting Post questions about KSH, CSH, SH, BASH, PERL, PHP, SED, AWK and OTHER shell scripts and shell scripting languages here. |
More UNIX and Linux Forum Topics You Might Find Helpful
|
||||
| Thread | Thread Starter | Forum | Replies | Last Post |
| Simple Question | aforball | UNIX for Dummies Questions & Answers | 3 | 03-04-2008 04:26 PM |
| simple sed question | funksen | Shell Programming and Scripting | 10 | 04-08-2007 05:54 PM |
| sed - simple question | scotty_123 | Shell Programming and Scripting | 13 | 03-29-2007 02:23 AM |
| Simple C question... Hopefully it's simple | Xeed | High Level Programming | 6 | 12-15-2006 02:29 PM |
| Ok simple question for simple knowledge... | Corrail | UNIX for Dummies Questions & Answers | 1 | 11-28-2005 01:03 PM |
|
|
LinkBack | Thread Tools | Search this Thread | Rate Thread | Display Modes |
|
||||
|
Simple awk If Satement question.
Trying to write an if statement, which calls2 or 3 functions from within it.
code: {if (($34 != "") && (NR != 1) && ($1 != "F")) less_than(34, 0, "S1002a") is_number(34,"S1002a") } But this is only treating the first function call, as part of the if. and always executes is_number. even if the if fails. Probably a simple error.....? |
| Bookmarks |
| Thread Tools | Search this Thread |
| Display Modes | Rate This Thread |
|
|