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Old 11-30-2006
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how to grep for a word and display only the word

Hi,

When we "grep" for a word in a file, it returns the lines containing the word that we searched for. Is there a way to display only the words and not the entire line containing them.

Thanks

Ananth
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Old 11-30-2006
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grep -o works on linux. Not sure of the Solaris/HP etc.

John Arackal
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Old 11-30-2006
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Or you could use sed to get a grep -o effect.

Code:
sed -n -e "s/.*\(search string\).*/\1/p" input.txt
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Old 06-19-2007
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Using grep -o in linux, it gives the list wherever the pattern appears. The file
input_file has "Hello World
Hi Hello Hello Hello
Hello
Bye
"
for eg: grep -o "Hello" input_file
Hello
Hello
Hello
Hello
Hello

sed -n -e "s/.*\(Hello\).*/\1/p" input_file
But in using sed, it prints One Hello per line, becoz of \1.

Is it any other way to print same as in linux.

TIA
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Old 06-20-2007
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Quote:
Originally Posted by knowledge_gain View Post
Using grep -o in linux, it gives the list wherever the pattern appears. The file
input_file has "Hello World
Hi Hello Hello Hello
Hello
Bye
"
for eg: grep -o "Hello" input_file
Hello
Hello
Hello
Hello
Hello

sed -n -e "s/.*\(Hello\).*/\1/p" input_file
But in using sed, it prints One Hello per line, becoz of \1.

Is it any other way to print same as in linux.

TIA
Code:
sed -n -e "s/\(Hello\)/\1\\
/gp" file | sed -n -e "s/.*\(Hello\).*/\1/p"
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