Are you sure that it's the correct date? When I convert it my way, it give me:

GNU Awk 3.1.5
$ TZ=UTC awk 'BEGIN {print strftime("%Y-%m-%d %T", 1211381313)}'
> 2008-05-21 14:48:33

date (GNU coreutils) 5.97
$ date --utc --date "1970-01-01 1211381313 sec" "+%Y-%m-%d %T"
> 2008-05-21 14:48:33

You are not passing $lastlog1 to Perl correctly, so it's effectively doing localtime(0). (The date it prints is Jan 1 1970 UTC 00:00:00 converted to your local time zone.)

If you are using awk anyway, the awk solution ripat posted would seem ideal.

Just for the record: the problem is here:

You try to expand variable ($lastlog1) inside single quotes. To prevent special characters like "$" from being interpreted by the shell is exactly what single quotes have been invented for.

The line will probably work writing it that way:

I hope this helps.

bakunin

do this.....

perl -le 'print scalar localtime('$a');'

and it returns

Wed May 21 07:48:33 2008