hye everybody :) ,
i'm new to the scripting world.. hope you guys can help me out with this one..
i'm trying to identify any directory under /tmp/saya that is created more than one day from the current date..
e.g, today is March 14, so any directory that has time stamp March 13 backwards, i... (2 Replies)
I have list of files named file_username_051208_025233.log. Here 051208 is the date and 025233 is the time.I have to run thousands of files daily.I want to put all the files depending on the date of running into a date directory.Suppose if we run files today they should put into 05:Dec:08... (3 Replies)
I need to increment a date value through shell script.
Input value consist of start date and end date in DATE format of unix.
For eg.
I need increment a date value of 1/1/09 to 31/12/09 i.e for a whole yr.
The output must look like
1/1/09
2/2/09
.
.
.
31/1/09
.
.
1/2/09
.
28/2/09... (1 Reply)
Hi Team,
I have thousands of TIF files which are converted from PDF. Below is a sample of it.
LH9406_BLANCARAMOS_2012041812103210320001.tif
LH9406_BLANCARAMOS_2012041812103210320002.tif
LH9406_BLANCARAMOS_2012041812103210320003.tif
LH9411_ANGENIAHUTCHINSON_2012041812102510250001.tif... (9 Replies)
Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted!
1. The problem statement, all variables and given/known data:
Here is what I am supposed to do, word for word from my assignment page:
1. Create/modify and print a... (2 Replies)
I want to create a directory based on date. I do not have date -d command. What I do have is:
either use "date" command to get current date
or DATE1=$(perl -e 'print scalar(localtime(time - 1 )), "\n";' |awk '{print $2,$3,$5}') |awk '{print $3}'can be modified to produce the desired year.... (3 Replies)
Can someone help me with the code wherein there is a file f1.txt with different column and 34 column have expiry date and I need to get that and compare with system date and if expiry date is <system date remove those rows and other rows should be moved to new file f2.txt .
I don't want to delete... (2 Replies)
I m working on shell scripting and I m stuck where in my .txt file there is column as expiry date and I need to compare that date with system date and need to remove all the rows where expiry date is less than system date and create a new .txt with update. (1 Reply)
Hi,
My question is how to calculate the quarter end date according to the current date in shell script? (2 Replies)
Discussion started by: Divya_1234
2 Replies
LEARN ABOUT PHP
datetime.setdate
DATETIME.SETDATE(3) 1 DATETIME.SETDATE(3)DateTime::setDate - Sets the date
Object oriented style
SYNOPSIS
public DateTime DateTime::setDate (int $year, int $month, int $day)
DESCRIPTION
Procedural style
DateTime date_date_set (DateTime $object, int $year, int $month, int $day)
Resets the current date of the DateTime object to a different date.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $year
- Year of the date.
o $month
- Month of the date.
o $day
- Day of the date.
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.3.0 | |
| | |
| | Changed the return value on success from NULL to |
| | DateTime. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
DateTime.setDate(3) example
Object oriented style
<?php
$date = new DateTime();
$date->setDate(2001, 2, 3);
echo $date->format('Y-m-d');
?>
Procedural style
<?php
$date = date_create();
date_date_set($date, 2001, 2, 3);
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2001-02-03
Example #2
Values exceeding ranges are added to their parent values
<?php
$date = new DateTime();
$date->setDate(2001, 2, 28);
echo $date->format('Y-m-d') . "
";
$date->setDate(2001, 2, 29);
echo $date->format('Y-m-d') . "
";
$date->setDate(2001, 14, 3);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-02-28
2001-03-01
2002-02-03
SEE ALSO DateTime.setISODate(3), DateTime.setTime(3).
PHP Documentation Group DATETIME.SETDATE(3)