The UNIX and Linux Forums  
Hello and Welcome from United States to the UNIX and Linux Forums! Thank You for Visiting and Joining Our Global Community.

Go Back   The UNIX and Linux Forums > Top Forums > UNIX for Advanced & Expert Users
.
google unix.com




View Single Post in the UNIX and Linux Forums - Click on the Thread or Permalink to View Entire Thread -->
  #4 (permalink)  
Old 10-23-2001
LivinFree's Avatar
LivinFree LivinFree is offline Forum Advisor  
Goober Extraordinaire
  
 

Join Date: Jul 2001
Location: Portland, OR, USA
Posts: 1,584
Well, first off, it helped me a lot to look at the code with indents in it:
Code:
#!/bin/ksh
count=1 
val=$2 
op=$1 
ans=0 
if [ $op = "-e" -o $op = "-o" ] 
then 
     if [ $op = "-e" ] 
     then 
     while [ $count -le $val ] 
     do 
     ans=`expr $count % 2` 
          if [ $ans -eq 0 ] 
          then 
          echo "$count \c " 
          count=`expr $count + 1` 
          fi 
     done 
     elif [ $op = "-o" ] 
     then 
     while [ $count -le $val ] 
     do 
     ans=`expr $count % 2` 
          if [ $ans -ne 0 ] 
          then 
          echo "$count \c " 
          count=`expr $count + 1` 
          fi 
     done 
     fi 
else 
while [ $count -le $val ] 
do 
echo "$count \c " 
count=`expr $count + 1` 
done 
fi
Now, the first thing I usually try when trying to figureout what my script is doing is to add a "set -x" line at the top of the script. That will echo out each step the shell is performing, so you can see what's going on...

So, The way I ran the script, (I'll give an example of what I think I saw trying to use the" -e 4 "option) it got stuck in a loop at:
+ ans=1
+ '[' 1 -eq 0 ']'
+ '[' 1 -le 4 ']'
++ expr 1 % 2
Ok, interesting... let's look at this. So, what the script is doing step by step:
Code:
     if [ $op = "-e" ]                       # This is true in our case
     then 
     while [ $count -le $val ]          # while 1 is less than or equal to 4
     do 
     ans=`expr $count % 2`         # ans = 1 % 2, or ans = 1
          if [ $ans -eq 0 ]                  # if ans (1) = 0, then continue... nope - can't continue
          then 
          echo "$count \c " 
          count=`expr $count + 1` 
          fi                                         # We're done, time to loop while waiting for ans to equal 0
Do you see what you problem is? Hint: $ans will always equal 1 in this case

Here's another (messier, but more info) way of doing it:
Code:
if [ "$op" = "-e" -o "$op" = "-o" ]
echo " if [ $op = -e -o $op = -o ]"
        then
echo "     then"
        if [ "$op" = "-e" ]
echo "     if [ $op = -e ] "
        then
echo "     then"
        while [ "$count" -le "$val" ]
echo "     while [ $count -le $val ] "
        do
echo "     do"
        ans=`expr $count % 2`
echo "     ans=`expr $count % 2` "
                if [ "$ans" -eq "0" ]
echo "          if [ $ans -eq 0 ] "
                then
echo "          then"
                echo -e "$count \c "
echo "          echo -e $count \c"
                count=`expr $count + 1`
echo "          count=`expr $count + 1`"
This way, you can watch your script in action... It almost looks as if it doesn't know when to exit, right?

You may need a little re-designing, but I think you're pretty much on the right track

(Ooh, and I appologize, I changed some of the "echo"'s to "echo -e"'s, since I was looking at this on a Linux system...

Does this help any?