Could someone please tell me the command to delete a line with a specific word and also deleting all lines below this line? I want this to be done without opening the file itself using SED in HP Unix?

e.g. I have a text file input.txt and with 4 lines of text below:

John 123 A--G
Chris 190 C--T
Mat 098 F--K
Mike 674 B--N
Pat 838 L--U

I want to delete the line which has string "098" and all lines below this line to look like the below:

John 123 A--G
Chris 190 C--T

I think below code can cater to ur need.

csplit filename "/`grep 098 filename`/"

will create files with xx prefix xx00 file will contain what u need.

This will help u ...

sed '/098/,$ d' filename

this deletes all lines starting from the first line having 098 uptill the end of file ...

Thanks everyone!
It worked!

Could someone please tell me how to make a Korn Shell to do the below:

I have the files below with the same format (different data) as mentioned previously and I want a shell to run "sed '/098/,$ d' filename" on all of the files in the directory.

list20051001.txt
list20051002.txt
list20051003.txt
...
list20051031.txt

Hi
Try the following:
for filename in `ls directory `
do
sed '/098/,$ d' $filename > $filename.1
mv $filename.1 $filename
done

Niyati
Thanks for your replay.
However I get the error below and it isn't working:


./testshell.ksh[4]: ls /MyFolder/Test.1: cannot create
mv: ls: cannot access: No such file or directory
mv: /MyFolder/Test.1: cannot access: No such file or directory
mv: ls: cannot access: No such file or directory


Below is the contents of testshell.ksh:

#!/bin/ksh
for filename in 'ls /MyFolder/Test'
do
sed '/098/,$ d' $filename > $filename.1
mv $filename.1 $filename
done


Below is the contents of /MyFolder/Test directory:
list1.txt list12.txt list2.txt list3.txt


Any help will be appreciated.