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Top Forums UNIX for Dummies Questions & Answers grepping the first 3 characters from a file Post 8559 by g-e-n-o on Sunday 14th of October 2001 06:51:25 PM
Old 10-14-2001
grepping the first 3 characters from a file

Hi

I was wondering if it's possible to use a command to get the first 3 characters of a line in a text file, I tried grep but it returns the whole line but I am only interested in the first 3 characters. Is this possible with grep or I need any other command?

Also is it possible deleting from a position to another in VI? For example delete from posistion 1 to 10 in all lines, I searched the whole VI man page but I couldnt find anything, only how to delete lines and words


Cheers
 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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