I am trying to write a shell script that will remove files in a directory based on the date. For instance, remove all files older than yesterday. Any ideas? (4 Replies)
Hi Friends,
Can anyone help me with this:
To get the count of files that are existing in a directory created on a perticular date like in the example (01/08) .(having same pattern for the filename)
ex:
FileName Creted Date
FILE001 01/08/2007
FILE005 ... (6 Replies)
hi all,
here is the description to my problem.
input parameters: $date1 & $date2
based on the range i need to select the archived files from the archived directory and moved them in to working directory.
can u please help me in writing the code to select the multiple files based on the... (3 Replies)
I have to write one script which will delete the files in the below passion.
If today is 17-Feb-2010 then the script delete only 17-JAN-2010 files from the directory.
Could you please help me, How will I delete the files when the year is leap year, if today is 30th Mar 2010 then how will... (1 Reply)
Hi
Howto view gzipped files with name file.gz.$DATE on a Solaris box (without unzipping first)
$ ls -lrt
total 4477
-rwxrwxr-x 1 oracle dba 569745 Apr 4 19:45 4_person2profileCon.txt.gz.04.04.11*
-rwxrwxr-x 1 oracle dba 3783 Apr 4 19:45... (4 Replies)
I wan to view files in a directory of a specific date. For example a log directory has log files . I want to view the list of the files which were generated on 01-May-2011.
Is there any option/proces to perform it?? (1 Reply)
Hi,
I need a script that moves files based on date to a folder. The folder should be created based on file date. Example is :
Date file name
----- --------
Oct 08 07:39 10112012_073952.xls
Oct 09 07:39 10112012_073952.xls
Oct 10 07:39 ... (6 Replies)
I have file listed like below
-rw-r--r--+ 1 test test 17M Nov 26 14:43 test1.gz
-rw-r--r--+ 1 test test 0 Nov 26 14:44 test2.gz
-rw-r--r--+ 1 test test 0 Nov 27 10:41 test3.gz
-rw-r--r--+ 1 test test 244K Nov 27 10:41 test4.gz
-rw-r--r--+ 1 test test 17M Nov 27 10:41 test5.gz
I... (5 Replies)
My unix version is IBM AIX Version 6.1
I tried google my requirement and found the below answer,
find . -newermt “2012-06-15 08:13" ! -newermt “2012-06-15 18:20"
But newer command is not working in AIX version 6.1 unix
I have given my requirement below:
Input:
atr files:
... (1 Reply)
Discussion started by: yuvaa27
1 Replies
LEARN ABOUT DEBIAN
bup-fuse
bup-fuse(1) General Commands Manual bup-fuse(1)NAME
bup-fuse - mount a bup repository as a filesystem
SYNOPSIS
bup fuse [-d] [-f] [-o] <mountpoint>
DESCRIPTION
bup fuse opens a bup repository and exports it as a fuse(7) userspace filesystem.
This feature is only available on systems (such as Linux) which support FUSE.
WARNING: bup fuse is still experimental and does not enforce any file permissions! All files will be readable by all users.
When you're done accessing the mounted fuse filesystem, you should unmount it with umount(8).
OPTIONS -d, --debug
run in the foreground and print FUSE debug information for each request.
-f, --foreground
run in the foreground and exit only when the filesystem is unmounted.
-o, --allow-other
permit other users to access the filesystem. Necessary for exporting the filesystem via Samba, for example.
EXAMPLE
rm -rf /tmp/buptest
mkdir /tmp/buptest
sudo bup fuse -d /tmp/buptest
ls /tmp/buptest/*/latest
...
umount /tmp/buptest
SEE ALSO fuse(7), fusermount(1), bup-ls(1), bup-ftp(1), bup-restore(1), bup-web(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-fuse(1)