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How can I match . (actual dot) using sed? How can I match . (actual dot) using sed?
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  #1  
Old 09-19-2005
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Join Date: Mar 2005
Posts: 48
How can I match . (actual dot) using sed?
Hi All,
How can I match . (actual dot) using sed? Please help.

Thanks
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  #2  
Old 09-19-2005
vino's Avatar
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Join Date: Feb 2005
Location: Bangalore, India
Posts: 2,683
You need to escape it with a \

Look at this.

Code:
sh-2.05b$ cat jing.txt
test
.
test.match
Code:
sh-2.05b$ sed -n -e '/\./p' jing.txt
.
test.match
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  #3  
Old 09-19-2005
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Join Date: Mar 2005
Posts: 48
Thanks vino.

But this doesn't work. I am looking for /./* (one or more of /./ and replace with a single /./

I tried dereferencing . and /
it doen't work. Please help.

Thanks
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  #4  
Old 09-19-2005
vino's Avatar
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Join Date: Feb 2005
Location: Bangalore, India
Posts: 2,683
This is going to be a confusing regex.

Code:
sed -e 's#\/\.\/\{1,\}#\/\.\/#g'
vino
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  #5  
Old 09-19-2005
Registered User
  

Join Date: Mar 2005
Posts: 48
Please see below:

cat 1 gives:

/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./

sed -e 's#\.\{1,\}#\.#g' 1 > 2

now see cat 2

/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./

It is not working.
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  #6  
Old 09-19-2005
vino's Avatar
Supporter (in vino veritas)
  

Join Date: Feb 2005
Location: Bangalore, India
Posts: 2,683
Yes the previous solution will not work.

But this should work

Code:
sh-2.05b$ cat jing.txt 
test
/./
test/.//.//./match
sh-2.05b$ sed  -e 's#\(\/\.\/\)*#\1#g' jing.txt 
test
/./
test/./match
vino
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  #7  
Old 09-19-2005
Registered User
  

Join Date: Mar 2005
Posts: 48
cat 1
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./

sed -e 's#\(\/\.\/\)*#\1#g' 1 > 2

cat 2
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./
/.//.//./

It is not working. Is there is special reason why this doesn't work?
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