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Full Discussion: To remove new line character
Top Forums UNIX for Advanced & Expert Users To remove new line character Post 80625 by vgersh99 on Wednesday 10th of August 2005 07:35:27 AM
Old 08-10-2005
Code:
sed -e 's#|\([^|][^|]*\)\\n\([^|][^|]*\)|#|\1\2|#g' file

 

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ISPUNCT(3)						   BSD Library Functions Manual 						ISPUNCT(3)

NAME
ispunct -- punctuation character test LIBRARY
Standard C Library (libc, -lc) SYNOPSIS
#include <ctype.h> int ispunct(int c); DESCRIPTION
The ispunct() function tests for any printing character, except for space (' ') or a character for which isalnum(3) is true. The value of the argument must be representable as an unsigned char or the value of EOF. In the ASCII character set, this includes the following characters (preceded by their numeric values, in octal): 041 ``!'' 042 ``"'' 043 ``#'' 044 ``$'' 045 ``%'' 046 ``&'' 047 ``''' 050 ``('' 051 ``)'' 052 ``*'' 053 ``+'' 054 ``,'' 055 ``-'' 056 ``.'' 057 ``/'' 072 ``:'' 073 ``;'' 074 ``<'' 075 ``='' 076 ``>'' 077 ``?'' 100 ``@'' 133 ``['' 134 ``'' 135 ``]'' 136 ``^'' 137 ``_'' 140 ```'' 173 ``{'' 174 ``|'' 175 ``}'' 176 ``~'' RETURN VALUES
The ispunct() function returns zero if the character tests false and returns non-zero if the character tests true. COMPATIBILITY
The 4.4BSD extension of accepting arguments outside of the range of the unsigned char type in locales with large character sets is considered obsolete and may not be supported in future releases. The iswpunct() function should be used instead. SEE ALSO
ctype(3), isalnum_l(3), iswpunct(3), ascii(7) STANDARDS
The ispunct() function conforms to ISO/IEC 9899:1990 (``ISO C90''). BSD
July 17, 2005 BSD
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