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Top Forums Shell Programming and Scripting Passing output of sed/echo to a variable Post 77841 by donflamenco on Wednesday 13th of July 2005 09:05:23 AM
Old 07-13-2005
Still giving me a "Variable Syntax" Error.
 

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CUBRID_ERROR_CODE_FACILITY(3)						 1					     CUBRID_ERROR_CODE_FACILITY(3)

cubrid_error_code_facility - Get the facility code of error

SYNOPSIS
int cubrid_error_code_facility (void ) DESCRIPTION
The cubrid_error_code_facility(3) function is used to get the facility code (level in which the error occurred) from the error code of the error that occurred during the API execution. Usually, you can get the error code when API returns false as its return value. PARAMETERS
This function has no parameters. RETURN VALUES
Facility code of the error code that occurred: CUBRID_FACILITY_DBMS, CUBRID_FACILITY_CAS, CUBRID_FACILITY_CCI, CUBRID_FACILITY_CLIENT EXAMPLES
Example #1 cubrid_error_code_facility(3) example <?php $conn = cubrid_connect("localhost", 33000, "demodb"); $req = @cubrid_execute($conn, "SELECT * FROM unknown"); if (!$req) { printf("Error facility: %d Error code: %d Error msg: %s ", cubrid_error_code_facility(), cubrid_error_code(), cubrid_error_msg()); cubrid_disconnect($conn); exit; } ?> The above example will output: Error facility: 1 Error code: -493 Error msg: Syntax: In line 1, column 15 before END OF STATEMENT Syntax error: unexpected 'unknown' SEE ALSO
cubrid_error_code(3), cubrid_error_msg(3). PHP Documentation Group CUBRID_ERROR_CODE_FACILITY(3)
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