Hello,
I have a requirement like -
I need to connect to specific Unix machine.That machine authenticates the user who is logging in. I am accessing from XP machine.
Is possible to supply the Username & Password along with Host name and port, from Windows command prompt? If so how?

If the target UNIX machine is running the telnet daemon, you can just telnet in from the Windows command prompt

i.e.

telnet hostname port

You'll then be prompted for a user name and password. If no port is specified it'll try the standard telnet port (23).

If you're using SSH on the server, then download a free SSH client such as PuTTY.

Cheers
ZB

Hello,
I would first like to thank you for the quick response. I guess I haven't projected the exact problem. I was using it in the same way as you said.
c:> telnet x.x.x.x 23

Thing is...I need to check the connectivity to different hosts, and all of them require authorization.We were checking them in the same way - first connect to the host,then supply the username & password. And then check for the remaining hosts similarly.It takes atleast 1-2 mins to test each host.We have to check different host with different login credentials. Also, this is a repetitive process which has to be done from time to time. So, this is consuming a lot of time.Is there any alternative to reduce this time taken?
I am looking for, if it is possible to write a batch file for it, but upto now I couldnot makeout any thing.

Also I have very little knowledge of Unix.

Thanks
KK

You could use something like expect for windows or python and write a script to automate this.

Do you have to use 'telnet' to test connectivity to differnet hosts ?

You can use 'ping' as well. Right ?

Just have a thought ... ;

I guess, from 'ping' command we can find only whether the host is reachable or not. But I dont think, the login crendiatials can be authenticated through this command.....

you can also use ftp on cygwin ... (substitute 1st jack with the username and the 2nd jack with the password) ... i would suggest you ping the host first though ...