This does indeed find every instance and print them out. Nice job!
What I need is for it to find the last instance and return that last one in a string variable so I can pass it onto the next step.
Do you have such an eloquent example of how this might be accomplished as well?
Much appreciated!
Without knowing what shell you're using, we can only guess at how the output of a command should be assigned to a shell variable. And, without knowing what operating system you're using, we have to make several other wild assumption that may not work in your environment, but the following seems to do what you seem to what on the MacOS system I'm using when using a Korn shell:
The command syntax in this script should work with other shells that perform basic command substitutions as required by the POSIX standards (such as bash). If you want to try this on a Solaris/SunOS system, you'll need to change awk to /usr/xpg4/bin/awk or nawk.
The above is a slight variation on the code RudiC suggested that only prints the last occurrence of the data pattern found in the input file,, save the result in a shell variable, and prints the contents of that shell variable before the script exits.
If a file named file contains the sample contents you provided in post #4 in this thread, the output produced by running the above script is:
Last edited by Don Cragun; 06-09-2017 at 05:34 AM..
Reason: Fix typo pointed out by RudiC: s/FS pat FS/FS pattern FS/
This User Gave Thanks to Don Cragun For This Post:
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