Hi,
I am new to using Sed. I have a file containg lines like the following:
INFORM----Test.pc:168:10/11/05 12:34:26 > some text goes here..
TRACE-----Test.pc:197:10/11/05 12:34:26 > some text goes here..
My requirement is to replace 10/11/05 12:34:26 with a string <RUNDATE> (including <... (4 Replies)
Hi,
I need to awk some data from some text files, basic stuff, eg:
awk '/phrase/ {print $1,$2,$3}' file
Which will print columns 1 to 3 of all lines containing "phrase"
But what if I wanted to pipe just one of the columns to a command (in my case a date converter) as in:
awk... (4 Replies)
Experts,
I am a beginner to Unix Shell Scripting
We have source as a flat file which contains CTRL+F character as the delimiter. We need to count the number of records in the file (CTRL+F) to perform file validation
Following command being used:
awk '{cnt+=gsub(//,"&")}END {print cnt}'... (4 Replies)
I would like to print result of multiple search pattern invoked from an one liner. The code looks like this but won't work
gawk -F '{{if ($0 ~ /pattern1/) pat1=$1 && if ($0 ~ /pattern2/) pat2=$2} ; print pat1, pat2}'
Can anybody help getting the right code? (10 Replies)
Hello,
Beginning with shell scipting, I'm trying to find in a csv file, the lines where the field related to hostname is displayed as an FQDN intead the hostname. (some lines are correct) and the to correct that inside the file:
Novell,11.0,UNIX Server,bscpsiws02,TxffnX1tX1HiDoyBerrzWA==... (2 Replies)
Experts:
LINE1 :This is line one The FIRST line of the file.
LINE2 :This is line two
LINE3 :This is line three with 8 fileds
LINE4 :This is line four
LINE5 :This is line five
LINE6 :This is line six with 8 fileds
I want to delete line 1, and then process the file and want to print lines... (2 Replies)
Dear Unix Forums,
I am hoping you can help me with a pattern matching problem.
What am I trying to do?
I want to replace multiple lines of a text file (that match a multi-line pattern) with a single line of text. These patterns can span several lines and do not always have the same number of... (10 Replies)
Hello is it possible with awk or sed to replace any white space with the previous line characters in the same position?
I am asking this because the file I have doesn't always follow a pattern.
For example the file I have is the result of a command to obtain windows ACLs:
icacls C:\ /t... (5 Replies)
Discussion started by: nakaedu
5 Replies
LEARN ABOUT FREEBSD
openpam_readword
OPENPAM_READWORD(3) BSD Library Functions Manual OPENPAM_READWORD(3)NAME
openpam_readword -- read a word from a file, respecting shell quoting rules
LIBRARY
Pluggable Authentication Module Library (libpam, -lpam)
SYNOPSIS
#include <sys/types.h>
#include <stdio.h>
#include <security/pam_appl.h>
#include <security/openpam.h>
char *
openpam_readword(FILE *f, int *lineno, size_t *lenp);
DESCRIPTION
The openpam_readword() function reads the next word from a file, and returns it in a NUL-terminated buffer allocated with malloc(3).
A word is a sequence of non-whitespace characters. However, whitespace characters can be included in a word if quoted or escaped according
to the following rules:
o An unescaped single or double quote introduces a quoted string, which ends when the same quote character is encountered a second time.
The quotes themselves are stripped.
o Within a single- or double-quoted string, all whitespace characters, including the newline character, are preserved as-is.
o Outside a quoted string, a backslash escapes the next character, which is preserved as-is, unless that character is a newline, in which
case it is discarded and reading continues at the beginning of the next line as if the backslash and newline had not been there. In all
cases, the backslash itself is discarded.
o Within a single-quoted string, double quotes and backslashes are preserved as-is.
o Within a double-quoted string, a single quote is preserved as-is, and a backslash is preserved as-is unless used to escape a double
quote.
In addition, if the first non-whitespace character on the line is a hash character (#), the rest of the line is discarded. If a hash charac-
ter occurs within a word, however, it is preserved as-is. A backslash at the end of a comment does cause line continuation.
If lineno is not NULL, the integer variable it points to is incremented every time a quoted or escaped newline character is read.
If lenp is not NULL, the length of the word (after quotes and backslashes have been removed) is stored in the variable it points to.
RETURN VALUES
If successful, the openpam_readword() function returns a pointer to a dynamically allocated NUL-terminated string containing the first word
encountered on the line.
The caller is responsible for releasing the returned buffer by passing it to free(3).
If openpam_readword() reaches the end of the line or file before any characters are copied to the word, it returns NULL. In the former case,
the newline is pushed back to the file.
If openpam_readword() reaches the end of the file while a quote or backslash escape is in effect, it sets errno to EINVAL and returns NULL.
IMPLEMENTATION NOTES
The parsing rules are intended to be equivalent to the normal POSIX shell quoting rules. Any discrepancy is a bug and should be reported to
the author along with sample input that can be used to reproduce the error.
SEE ALSO openpam_readline(3), openpam_readlinev(3), pam(3)STANDARDS
The openpam_readword() function is an OpenPAM extension.
AUTHORS
The openpam_readword() function and this manual page were developed by Dag-Erling Smorgrav <des@des.no>.
BSD September 12, 2014 BSD